How to sort by size

This is a discussion on How to sort by size within the C++ Programming forums, part of the General Programming Boards category; Hi people! I would love any help on this one: I have a list of lists list<list<int>*> and I need ...

  1. #1
    Disturbed Boy gustavosserra's Avatar
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    How to sort by size

    Hi people! I would love any help on this one:
    I have a list of lists list<list<int>*> and I need to sort it by the size of the inner list. I only need to know how to declare a Compare function (I saw this kind of function in references, but I donīt know how to declare it).
    So, I coulde use: myList.sort( compare_function );
    Nothing more to tell about me...
    Happy day =)

  2. #2
    Registered User
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    I think it the compare function should look like this.

    Code:
    bool Compare(const list<int> &l1, const list<int> &l2)
    {
        return l1.size() < l2.size();
    }
    That should sort in increasing order according to size.

  3. #3
    Disturbed Boy gustavosserra's Avatar
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    Actually, after a lot of study, I had discover that the compare function returns an int, I think this is because an int can show three results: less, equal and greater.
    But thanks for the reply
    Nothing more to tell about me...
    Happy day =)

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