Outputting a menu

This is a discussion on Outputting a menu within the C++ Programming forums, part of the General Programming Boards category; This program is supposed to be a menu system for holiday destinations. As you can see, no menu is displayed, ...

  1. #1
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    Outputting a menu

    This program is supposed to be a menu system for holiday destinations. As you can see, no menu is displayed, but the user simply has to press a letter and the name of the country is displayed as destination.
    So, could anyone give me a better way to output my program?


    Code:
    //---------------------------------------------------------------------------
    #include<conio>
    #include<iostream>
    #include<cstring>
    #pragma hdrstop
    using namespace std;
    
    //---------------------------------------------------------------------------
    
    #pragma argsused
    int main(int argc, char* argv[])
    {
       char choice;
    
       while ( ( choice = cin.get() ) != 'q' )
       {
       cin.ignore();
       switch ( choice )
    
       {
       case 'a':
    
       cout << "Chosen destination is Australia" << endl;
       break;
    
       case 'u':
    
       cout << "Chosen destination is United States" << endl;
       break;
    
       case 't':
    
       cout << "Chosen destination is Thailand" << endl;
       break;
    
       case 'f':
    
       cout << "Chosen destination is France" << endl;
       break;
    
       case 'g':
       cout << "Chosen destination is Germany" << endl;
       break;
    
       default:
       cout << "Invalid Choice" ;
       }
       }
    
       return 0;
    }
    //---------------------------------------------------------------------------

  2. #2
    End Of Line Hammer's Avatar
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    Apr 2002
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    6,231
    There's probably better ways with iterators etc, but here's one attempt:
    Code:
    #include <iostream>
    
    using namespace std;
    
    const string Options[] = 
    {
      "Destination 1",
      "Destination 2",
      "Destination 3",
      "Destination 4"
    };
    
    int main(void)
    {
      
      for (int i = 0; i < sizeof(Options)/sizeof(Options[0]); i++)
      {
        cout <<Options[i] <<endl;
      }
    }
    When all else fails, read the instructions.
    If you're posting code, use code tags: [code] /* insert code here */ [/code]

  3. #3
    Comment your source code! Lynux-Penguin's Avatar
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    533
    i dont think class string supports the '<<' operator for cout

    so either add this:
    Code:
    ostream& operator<<(ostream& out, string& str)
    {
        out<<str.c_str();
        return out;
    }
    or when u cout the string do
    Code:
        cout <<Options[i].c_str()<<endl;
    -LC
    Asking the right question is sometimes more important than knowing the answer.
    Please read the FAQ
    C Reference Card (A MUST!)
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  4. #4
    Registered User jlou's Avatar
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    Originally posted by Lynux-Penguin
    i dont think class string supports the '<<' operator for cout
    Actually, I think '<<' works fine with string. It worked for me in MSVC 6.0. If you use the deprecated header then you will get a compile error, but if you use <iostream> like Hammer did in his example it should work fine.

  5. #5
    Registered User
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    cout << is most deffinatly overloaded for std::string's. It would be silly not to.

  6. #6
    End Of Line Hammer's Avatar
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    >>i dont think class string supports the '<<' operator for cout
    Are you seriously suggesting I'd post an answer using code that doesn't compile
    When all else fails, read the instructions.
    If you're posting code, use code tags: [code] /* insert code here */ [/code]

  7. #7
    Registered User jlou's Avatar
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    Originally posted by Hammer
    Are you seriously suggesting I'd post an answer using code that doesn't compile
    That's funny, especially considering the posted code doesn't compile . . . (requires #include <string> for me)

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