Array of pointer

This is a discussion on Array of pointer within the C++ Programming forums, part of the General Programming Boards category; Can I create an array of pointer with new operator?...

  1. #1
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    Array of pointer

    Can I create an array of pointer with new operator?

  2. #2
    It's full of stars adrianxw's Avatar
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    Yes. Where are you having trouble?
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    I'm sorry. Because I've just learned C++, I'm still confuse about pointer in C++. Would you like to tell me how to create a pointer of array with new operator?

  4. #4
    pronounced 'fib' FillYourBrain's Avatar
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    Type **ptr_array;
    ptr_array = new Type *[256];
    "You are stupid! You are stupid! Oh, and don't forget, you are STUPID!" - Dexter

  5. #5
    End Of Line Hammer's Avatar
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    I'm not sure exactly what you want, so here goes...

    A dynamically created array of int pointers:
    int **myArray = new int*[10];

    A dynamically created array of ints
    int *myArray = new int[10];

    Clarify what you want, try coding it yourself, and post your attempt here if you have trouble.
    When all else fails, read the instructions.
    If you're posting code, use code tags: [code] /* insert code here */ [/code]

  6. #6
    *******argv[] - hu? darksaidin's Avatar
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    Can somebody tell me if this is correct, too ?

    Code:
    typedef int* pint;
    pint *ppiRowIndices;
    
    ....
    
    ppiRowIndices= new pint[iCount];
    It seems to work but looks differnt then the code posted here. It wouldn't be too cool if it only worked because there are no overflow checks etc.

  7. #7
    pronounced 'fib' FillYourBrain's Avatar
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    basically you did the same thing. the typedef gives a name to an int * is the only difference.
    "You are stupid! You are stupid! Oh, and don't forget, you are STUPID!" - Dexter

  8. #8
    *******argv[] - hu? darksaidin's Avatar
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    Originally posted by FillYourBrain
    basically you did the same thing. the typedef gives a name to an int * is the only difference.
    I did that because new didn't accept the "int*". Thats why I wondered if my code is correct. pint is just another name for "int*", so why would it accept that but not "int*"? Anyway, if it's correct and it works I'm happy.

    thanks!

  9. #9
    pronounced 'fib' FillYourBrain's Avatar
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    I did that because new didn't accept the "int*".
    what compiler? can I see that line of code?
    "You are stupid! You are stupid! Oh, and don't forget, you are STUPID!" - Dexter

  10. #10
    Toaster Zach L.'s Avatar
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    Also, once you have your array, remember that none of those pointers have been initialized.
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    Thank you. It's very helpful for me.

  12. #12
    mustang benny bennyandthejets's Avatar
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    I understand the workings of an array of pointers, but I'm not sure about the application of it. Would this be a valid example?

    Code:
    void InitializePCharArray(char **array,int num)
    {
    for (int i=0;i<num;i++)
        *((&array)[num])=GetInput(); //return type char *
    }
    
    int main()
    {
    char **PPCharArray=new char*[10];
    
    InitializePCharArray(PPCharArray,10);
    return 0;
    }
    I'm really lost here!
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  13. #13
    mustang benny bennyandthejets's Avatar
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    Wow that was some serious overkill ey? I think I understand now, I drew a whole lot of diagrams out on paper, with arrows, boxes, and everything.
    benforbes@optusnet.com.au
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