My new programm......having problems.

So I started this new program and I can't seem to get past the first step.

Code:

---


#include <iostream>
using namespace std;

int main()
{
char Menu, Start, Recall, Exit,choice;

cout <<"Hello, how are we today?" <<endl;
cout <<"|===================|" <<endl;
cout <<"|      (M)enu                          |" <<endl;
cout <<"|      (S)tart                          |" <<endl;
cout <<"|      (R)ecall                          |" <<endl;
cout <<"|      (E)xit                            |" <<endl;
cout <<"|______________________|" <<endl;
cout <<"Please choose a destination" <<endl;
cin >>choice;
  if (choice == Menu)
  {
      cout <<"You are in menu now!" <<endl;
  }
system("pause");
return 0;
}

---

The menu choice option won't work. Any ideas?

I think it's the if statement. It should be

if(choice == 'M')
cout << "You are in menu now!" << endl;

Quote:

---

Originally posted by RealityFusion
So I started this new program and I can't seem to get past the first step.

Code:

---


#include <iostream>
using namespace std;

int main()
{
char Menu, Start, Recall, Exit,choice;

const char Menu = 'M';
const char Start = 'S';
const char Recall = 'R';
const char Exit = 'E';
char choice;

cout <<"Hello, how are we today?" <<endl;
cout <<"|===================|" <<endl;
cout <<"|      (M)enu                          |" <<endl;
cout <<"|      (S)tart                          |" <<endl;
cout <<"|      (R)ecall                          |" <<endl;
cout <<"|      (E)xit                            |" <<endl;
cout <<"|______________________|" <<endl;
cout <<"Please choose a destination" <<endl;
cin >>choice;
  if (choice == Menu)
  {
      cout <<"You are in menu now!" <<endl;
  }
system("pause");
return 0;
}

---

The menu choice option won't work. Any ideas?

---

If you make a comparison (choice == Menu) you have to have declared both variables before. In your program you declared choice when typing it in, but you never declared what Menu is.
I added const in front of the variables, since I'm guessing that they won't be changed...

I changed the code a bit and it still won't work.

Code:

---

#include <iostream>
using namespace std;

int main()
{
 char m,s,r,e,choice;
 

cout <<"Hello, how are we today?" <<endl;
cout <<"|======================|" <<endl;
cout <<"|      (M)enu        |" <<endl;
cout <<"|      (S)tart        |" <<endl;
cout <<"|      (R)ecall      |" <<endl;
cout <<"|      (E)xit        |" <<endl;
cout <<"|______________________|" <<endl;
cout <<"Please choose a destination" <<endl;
cin >>choice;
  if (choice == m)
  {
      cout <<"You are in menu now!" <<endl;
  }
system("pause");
return 0;
}

---

Change this:

Code:

---

if (choice == m)
{
    cout <<"You are in menu now!" <<endl;
}

---

to:

Code:

---

if (choice == 'm')
{
    cout <<"You are in menu now!" <<endl;
}

---

Without the apostrophe's, you are comparing it to a variable, not a value. The VARIABLE m doesn't equal anything unless you initialize it.

Your checking to see if the user's input is equal to an uninitialized variable. You have to assign some kind of value to your chars:

Code:

---

char m='m'; //one way to do it
const char s='s'; //this way the value assigned to the variable cant change

---

or if you want you can:

Code:

---

#define m 'm'

---

at the top of your program.

or even simpler (but without variables)

Code:

---

if (choice=='m') //but remember if the user inputs 'M' this wont work since it is case sensitive ('m' is a different character)

---

Thanks, that fixed the problem!
So the single aposthropy's (sp?) initialize things. I was kind of thinging that. Since M was declared as a char as well as choice it wouldn't output my if statement because choice and m are not the same value. It makes sense. Thank you.