Thread: how to modifying a user verified string?

Well, I'm still a beginner in C++, I use microsoft visual C++ as a compiler.
I want to know how to modify a text that the user has typed 'n it was stored into a string variable, like the following example:

Code:

#include 
int main() 
{ 
char string[14]; 
cin.getline(string, 14, '\n'); 
cout<<string<<endl; 
return 0; 
}

For example, if the user types "you" it appears in the cout as "me"

alpha, your examples won't work. Even though the poster said they were using a string variable, they were actually using a char array, or c-style string, and you can't set a char array with length 14 to the word "me" which is of length 3(2 plus one for the \0 that is tacked on) or you will get the following error:

cannot convert from 'char [3]' to 'char [14]'

Instead, you have to modify a c-style string character by character like this:

Code:

string[0] = 'm';
string[1] = 'e';
string[2] = '\0';
for(int i = 3; i<14 ; i++)
{
    string[i]='\0';
}

Similarly, char string[14] that contains "you" will never equal "you" in this conditional:

if(string == "you")

You have to use the cstring function strcmp() as Wledge (has now) posted.

>>Instead, you have to modify a c-style string character by character like this:
strcpy

I meant that if the user typed a sentence CONTAINING "you" the same sentence is outputed to the user with the exception of chaning "you" to "me".
eg. when the user types "as well as you" it is couted as "as well as me"..

Thanks.
Memo

All right, can't think of any code right now, but I'll give you some pseudo-code and see if you can work it from there.

Code:

char input[20], output [20], check[4], ch;

copy what the user types into input;

for( int i = 0; input[i] != '\0')

  read one char at at a time into ch;
  if (ch == 'y')
  {
     copy that and the next two chars into check;
     if check == "you"
        append "me" to the end of output;
  }
  else
     append ch to the end of output;

Well, hope that helps you.
I know I said no code, but sometimes it's easier to do it with code than write it in human language.
It might run faster if you put what's in the if in the else and viceversa.

Or, instead of getting overly complicated, you could use strstr:

char *strstr( const char *string, const char *strCharSet );

Example from help files:

Code:

#include <string.h>
#include <stdio.h>

char str[] =    "lazy";
char string[] = "The quick brown dog jumps over the lazy fox";
char fmt1[] =   "         1         2         3         4         5";
char fmt2[] =   "12345678901234567890123456789012345678901234567890";

void main( void )
{
   char *pdest;
   int  result;
   printf( "String to be searched:\n\t%s\n", string );
   printf( "\t%s\n\t%s\n\n", fmt1, fmt2 );
   pdest = strstr( string, str );
   result = pdest - string + 1;
   if( pdest != NULL )
      printf( "%s found at position %d\n\n", str, result );
   else
      printf( "%s not found\n", str );
}

Then just copy the string from before the located word, strcat "me" instead of "you", then strcat the remainder of the string.

Loop up: strstr, strncpy, strncat.

strncpy and strncat will copy/append n bytes of your string, which is what you'll need to be doing.