operator = overloading

This is a discussion on operator = overloading within the C++ Programming forums, part of the General Programming Boards category; in this example class what will happen to the year of birth? Will it have a garbage value? Code: Car* ...

  1. #1
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    operator = overloading

    in this example class what will happen to the year of birth? Will it have a garbage value?


    Code:
    Car* m_pCar;
    >     double m_salary;
    >     const int m_yearOfBirth;
    >public:
    >     Person(int yearOfBirth, Car* pCar, double salary):
    >      m_yearOfBirth(yearOfBirth){
    >           m_pCar=pCar;
    >           m_salary=salary;
    >      }
    >
    >      Person(const Person& other): m_yearOfBirth(other.m_yearOfBirth){
    >           m_pCar=other.m_pCar;
    
    This will make the two persons share the same car.   
    
    >           m_salary=other.m_salary;
    >      }
    >      
    >      const Person& operator=(const Person& other){
    
    So what happend to the year of Birth? 
    
    
    >      m_pCar= other.m_pCar;
    > m_salary= other.m_salary;
    >      }
    >
    >      ~Person(){
    >           delete m_pCar;
    >      }
    >

  2. #2
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    Re: operator = overloading

    Originally posted by noob2c
    So what happend to the year of Birth?
    In operator=?Nothing.yearofbirth is const,since the constructor call and till the destructor call.

    Instead you should take care of this
    > m_pCar= other.m_pCar;
    Uh,thats wrong,now two pointer point to one memory location.

  3. #3
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    what do u mean that nothing happens?

  4. #4
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    "in this example class"

    What example class?? I don't see a class anywhere in your code.

    yearOfBirth will have whatever value you use as a parameter when calling the Person constructor.

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