Very simple question

This is a discussion on Very simple question within the C++ Programming forums, part of the General Programming Boards category; Hello everyone, I'm new to this board and new to C++ but I have a question about a program I've ...

  1. #1
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    Question Very simple question

    Hello everyone, I'm new to this board and new to C++ but I have a question about a program I've run into in Sams Teach Yourself C++ in 21 Days. I've written it correctly and when I tried to compile it I got errors (I'm not supposed to get any with this piece) and since I'm new to this, I can't exactly figure out what the problem is. Here it is, tell me what you think:

    Code:
    #include <iostream.h>
    
    int main()
    {
    	int x = 5;
    	int y = 7;
    	cout "\n";
    	cout << x + y << " " << x * y;
    	cout "\n";
    	
    	return 0;
    }
    Simplicity at it's best But I figured it's worth a try...these are the errors I get:
    Line 7: error C2143: syntax error : missing ';' before 'string'
    Line 9: error C2143: syntax error : missing ';' before 'string'

    Thanks

    PS - Sorry to those of you that see this as a waste of your time.

  2. #2
    Registered User slaveofthenet's Avatar
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    For single characters you use ' ' to enclose them, not " ", ie cout << '\n';.
    Detailed understanding of language features - even of all features of a language - cannot compensate for lack of an overall view of the language and the fundamental techniques for using it. - Bjarne Stroustrup

  3. #3
    carry on JaWiB's Avatar
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    add "<<" after cout:
    Code:
    cout<<"\n";
    cout<<endl;
    cout<<"\\n creates a new line, while endl creates a new line and flushes the output buffer";
    "Think not but that I know these things; or think
    I know them not: not therefore am I short
    Of knowing what I ought."
    -John Milton, Paradise Regained (1671)

    "Work hard and it might happen."
    -XSquared

  4. #4
    Registered User harryP's Avatar
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    Code:
    #include <iostream.h>
    
    int main()
    {
    	int x = 5;
    	int y = 7;
    	cout "\n";
    	cout << x + y << " " << x * y;
    	cout "\n";
    	
    	return 0;
    }
    Your problem is you don't have the '<<' operator (I don't remember the name offhand) on line 7. It should be this:

    Code:
    #include <iostream.h>
    
    int main()
    {
    	int x = 5;
    	int y = 7;
    	cout << "\n";
    	cout << x + y << " " << x * y;
    	cout "\n";
    	
    	return 0;
    }
    Brendan
    Draco dormiens nunquam titallandus.
    Console Graphics Library: http://www.geocities.com/steve_alberto/cgl.html

  5. #5
    Registered User harryP's Avatar
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    Ah I was beaten to it.

    Brendan
    Draco dormiens nunquam titallandus.
    Console Graphics Library: http://www.geocities.com/steve_alberto/cgl.html

  6. #6
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    Thanks

    Awesome, thanks all. Turns out I needed the << at the beginning...good to know

  7. #7
    verbose cat
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    Originally posted by harryP

    Your problem is you don't have the '<<' operator (I don't remember the name offhand) on line 7. It should be this:
    The << is called the "insertion operator" as it inserts the data on the right into the stream on the left. Very helpful to remember it that way too as it reminds you that cout is a stream object and you can do all the nifty things with it that you can do with streams. Hope this helps.

    -jEssYcAt

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