I have created a float pointer the following way.
float *tempPtr;
tempPtr = new float(14);
I then display what is in the tempPtr.
tempPtr[0]
tempPtr[1]
.....
.....
tempPtr[12]
tempPtr[13]
In the first 13 (0 thru 12) positions I see stuff like 1.63204e-37, which is OK but in the 14 (13) position I see =-NaN.
Does anybody know what -Nan is? If I try and initialize just that last location my job goes down with an error.
Thanks.
NaN - Not a Number.
To dynamically allocate an array, you should use square brackets.
Your code is allocating a single float and initialising it with the value 14. Since the "array" element 14 does not exist, your attempt to write to it is causing some kind of access violation.Code:float *p; p = new float[14]; ... delete [] p;
Wave upon wave of demented avengers march cheerfully out of obscurity unto the dream.
What doesOriginally posted by adrianxw
NaN - Not a Number.
To dynamically allocate an array, you should use square brackets.
do then ? Obviously it seems to compile so it must have some kind of meaning for the compilerCode:float(14);
edit: thanks Adrianxw!
Last edited by darksaidin; 07-25-2003 at 08:14 AM.
I was editing my last post to clarify that!
Wave upon wave of demented avengers march cheerfully out of obscurity unto the dream.
THE BRACKETS That was it. I guess it just takes a second pay of eyes to see the simple things.
Thanks again.
It calls the default constructor for a single float. In other words it initializes the one float it creates to 14.Originally posted by darksaidin
What does
do then ? Obviously it seems to compile so it must have some kind of meaning for the compilerCode:float(14);
"You are stupid! You are stupid! Oh, and don't forget, you are STUPID!" - Dexter
int i1 = 1;
int i2(1);
both of these are the same.
"You are stupid! You are stupid! Oh, and don't forget, you are STUPID!" - Dexter
