functions

hello everyone (again)
for some strange reason, my compiler doesn't compile functions
of course, it's probably my mistakes

so i declared the function

int blah(int blah1, int blah2);

int main()
{
yeah yeah yeah;

blah(blah1, blah2);
return 0;
}

int blah(int blah1, int blah2)
{
the code;
return 0;
}

my code (like this one) will not compile.
the compiler says :

passing 'int' to argument 1 of 'blah(int *, int)' lacks a cast.
I did the functions according to tutorial, and i checked extra carefully so that there are no spelling errors.any help would be greatly appreciated

thanks

Please copy and paste your actual code into the message.

well... the code is far from being complete, and don't laugh at me! i'm a n00bie

//Program brought to you by: Derek Kwok
//Created on July 21, 2003
//Last Modified on July 21, 2003
//File name: ttt.cpp

#include <iostream.h>

int startgame(int keepcounter[10], int userchoice);

int main()
{
int tic_tac_toe[3][3], userchoice, keepcounter[10], game, counter;

//Warm welcome message
cout << "Welcome to Derek's Mega Project #2 - Tic Tac Toe" << endl;
cout << "ENJOY!" << endl;

//The tic tac toe board
cout << endl;
cout << endl;
cout << " 1 | 2 | 3 " << endl;
cout << " ---|---|--- " << endl;
cout << " 4 | 5 | 6 " << endl;
cout << " ---|---|--- " << endl;
cout << " 7 | 8 | 9 " << endl;

//Reset of the keep counter
for (counter = 0; counter < 9; counter++)
{
keepcounter[counter] = 0;
}

startgame(keepcounter[10], userchoice);
return 0;
}


//Start game function
int startgame(int keepcounter[10], int userchoice)
{
cout << endl;
cout << "Please enter the number where u would like to play at: ";
cin >> userchoice;

//check if that place is already played at
if (keepcounter[userchoice] == 1)
{
cout << "Sorry, you can't play there." << endl;
startgame(keepcounter[10], userchoice);
}

else if (keepcounter[userchoice] == 0)
{
keepcounter[userchoice] = 1;
cout << "You have chosen to play at spot #" << userchoice << endl;
}
return 0;
}

Someone else will surely say this, so I will get it out of the way... USE [CODE] TAGS!

Code:

//Program brought to you by: Derek Kwok
//Created on July 21, 2003
//Last Modified on July 21, 2003
//File name: ttt.cpp

#include <iostream.h>

int startgame(int *keepcounter, int userchoice);

int main()
{
	int tic_tac_toe[3][3], userchoice, keepcounter[10], game, counter;

	//Warm welcome message
	cout << "Welcome to Derek's Mega Project #2 - Tic Tac Toe" << endl;
	cout << "ENJOY!" << endl;

	//The tic tac toe board
	cout << endl;
	cout << endl;
	cout << " 1 | 2 | 3 " << endl;
	cout << " --+---+--- " << endl;
	cout << " 4 | 5 | 6 " << endl;
	cout << " --+---+--- " << endl;
	cout << " 7 | 8 | 9 " << endl;

	//Reset of the keep counter
	for (counter = 0; counter < 9; counter++)
	{
		keepcounter[counter] = 0;
	}

	startgame(keepcounter, userchoice);
	return 0;
}


//Start game function
int startgame(int *keepcounter, int userchoice)
{
	cout << endl;
	cout << "Please enter the number where u would like to play at: ";
	cin >> userchoice;

	//check if that place is already played at
	if (keepcounter[userchoice] == 1)
	{
		cout << "Sorry, you can't play there." << endl;
		startgame(keepcounter, userchoice);
	}

	else if (keepcounter[userchoice] == 0)
	{
		keepcounter[userchoice] = 1;
		cout << "You have chosen to play at spot #" << userchoice << endl;
	}
	return 0;
}

Try not to pass arrays into a function's parameter, instead see if you can use Pointers, and check the pointer's length.

"You can also pass an array to a function, but in this case the array is not copied, even though a pass-by-value method of passing arguments still applies. The array name is converted to a pointer, and a copy of the pointer to the beginning of the array is passed to the function. This is quite advantageous, as copying large arrays could be very time consuming." --C++ Tutorial from Wrox

also whenever you use arrays think of them as a chain of pointers. And that using the []s derefrences the pointer but leaving them out is like using the pointer without the *.

Which is why you cant call a function like
startgame(myarray[10],blah);
lets say the tenth number in myarray was 17
what your really doing is something like:
startgame(17,blah);
and your not telling the function where the array is.

But as a general note, try to avoid passing arrays into functions, it avoids confusion



-LP

i'm still not quite getting it
about pointers and stuff..

so if i were to pass an array to a function, i should use a pointer instead

something like this?

int blah(int *pointer);

int main()
{
int x[10];
int *pointer;

pointer = &x;

blah(*pointer);
return 0;
}

int blah(int *pointer)
{
cout << *pointer;
return 0;
}


would this code work?
pointers are too confusing. -__-;;

THANKS SO MUCH! >_<
i understand it at last

i can't believe i didn't get something so simple =D