How can I read one number at a time?

Bad_Scooter · 07-18-2003, 09:19 PM

How can I read in one number at a time from a string of numbers?
Something like this:

1429943983...

I want to read in the one, then the four, and so on. My first thought was to use get. Something like fin.get(number); But this statement only seems to accept a char, not an int. I am at a loss, short of reading in a char and converting to an int through 10 if statements. Any help would be great.

quzah · 07-18-2003, 09:35 PM

Do that. Read a character, convert it to a number. Subtract the character value of zero from the character number to get its numeric value. Example:

cout << "'4' - '0' = " << '4' - '0' << endl;

Enjoy.

Quzah.

Bad_Scooter · 07-18-2003, 09:58 PM

Thanks, that's what I'll do, I just thought there may have been an easier way.

07-18-2003, 09:19 PM	#1
Bad_Scooter Registered User Join Date: Mar 2003 Posts: 15	How can I read one number at a time? How can I read in one number at a time from a string of numbers? Something like this: 1429943983... I want to read in the one, then the four, and so on. My first thought was to use get. Something like fin.get(number); But this statement only seems to accept a char, not an int. I am at a loss, short of reading in a char and converting to an int through 10 if statements. Any help would be great.
Bad_Scooter is offline

07-18-2003, 09:35 PM	#2
quzah +++ OK NO CARRIER Join Date: Oct 2001 Posts: 10,628	Do that. Read a character, convert it to a number. Subtract the character value of zero from the character number to get its numeric value. Example: cout << "'4' - '0' = " << '4' - '0' << endl; Enjoy. Quzah. __________________ Hundreds of thousands of dipshits can't be wrong. Are you up for the suck?
quzah is offline

07-18-2003, 09:58 PM	#3
Bad_Scooter Registered User Join Date: Mar 2003 Posts: 15	Thanks, that's what I'll do, I just thought there may have been an easier way.
Bad_Scooter is offline

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