Is it possible to overload the subscript operator? If so, could someone please provide an example of doing so. I know that this must sound rather odd, but I am curious. Thank you in advance for any information you may provide! ^_^
Overloading Operators
Is it possible to overload the subscript operator? If so, could someone please provide an example of doing so. I know that this must sound rather odd, but I am curious. Thank you in advance for any information you may provide! ^_^
Yes, here's an example from one of my programs.
Code:template <class T> T& linked_list<T>::operator[](int index) { if (index < 0 || index >= list_size) throw out_of_bounds(); node<T> *temp; temp = front; for (int i = 0; i < index; ++i) { temp = temp->next; } return temp->value; }
Detailed understanding of language features - even of all features of a language - cannot compensate for lack of an overall view of the language and the fundamental techniques for using it. - Bjarne Stroustrup
Subscripting
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Only the following operators cannot be overloaded:
.
.*
::
Additionally, ?: cannot be overloaded.
The word rap as it applies to music is the result of a peculiar phonological rule which has stripped the word of its initial voiceless velar stop.
Thank you all for your help! You have completly answered my question!
The sizeof operator cannot be overloaded either, just to make the list completeOriginally posted by Zach L.
Only the following operators cannot be overloaded:
.
.*
::
Additionally, ?: cannot be overloaded.
For completeness, neither can typeid.
The word rap as it applies to music is the result of a peculiar phonological rule which has stripped the word of its initial voiceless velar stop.
