Thread: How to call the constructor in this case

If you have an array of objects that need constructing, then that object must have a default constructor. If a default constructor doesn't work in your case - then use an array of pointers and allocate each element.

gg

I didn't look at your code, but I think I have a pretty good idea of what you're asking.

If you have an array of objects that need constructing, then that object must have a default constructor. If a default constructor doesn't work in your case - then use an array of pointers and allocate each element.

I don't think this is true, consider the following:

Code:

class Piece
{
public:
    Piece(int id) : m_id(id) {};
    ~Piece() {};

protected:
    int m_id;
};

...

Piece Pieces[5] = { Piece(0), Piece(1), Piece(2), Piece(3), Piece(4) };

I come back to the boards and get schooled by Eibro - with a cool new avatar too!

gustavosserra, it is possible, use static initialization like Eibro showed.

gg

Originally posted by gustavosserra
But I have a 8x8 matrix! This means calling the constructor 64 times!

Yep, its gotta happen somehow. Either the compiler will generate the code for you (if you have a default constructor) or you will have to do it yourself with static initialization or a for loop and pointers.

gg