error converting string to char array

[COBOL2C++]

Can anyone tell me why the folowing is getting on error.

string orig = 123456789
string newSSN;
newSSN = orig.substr(0, 3) + "-" +
orig.substr(3, 2) + "-" +
orig.substr(5, 4);

char * newString = new char[strlen newSSN)+1];

ERROR = cannot convert `newSSN' from type `string' to type `const char *'

I am trying to convert string newSSN to a char array ,newString, but I keep getting that error.

Thanks,

[ripper079]

string orig = "123456789"; //missing semicolon and "
//Prefer
//string orig("123456789");

char * newString = new char[strlen (newSSN.c_str())+1];

strlen accepts char * and not string. For more information check out this and this

[Wledge]

char * newString = new char[newSSN.size() + 1];

[COBOL2C++]

Thanks,

I added that code and was able to compile and run it but I had expected to see the value in newSSN also in newString. Instead newString was empty. Any thouhgts on that.

Maybe I am on the wrong track.

Thanks for any help you may offer.

[thefroggy]

char * newString = new char[newSSN.size() + 1];
strcpy(newString, newSSN.c_str());

[Wledge]

Originally posted by thefroggy

char * newString = new char[newSSN.size() + 1];
strcpy(newString, newSSN.c_str());

Better..

char *newString = new char[newSSN.size() + 1];
newSSN.copy(newString,string::npos);
newString[newSSN.size()] = 0;

[COBOL2C++]

Thanks for all your help. It worked.