sad overly newbish question on output

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  1. #1
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    sad overly newbish question on output

    In C++ how may I ask can I output a string as with fgets in C. What is its equivalent.

  2. #2
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    I may be wrong, as I started with C++, but I believe printf and cout (iostream.h, but only in console applications) will suit what you're looking for.

  3. #3
    Pursuing knowledge confuted's Avatar
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    I'm not sure if a string (if you're talking about the STL class) will work with printf();. Use cout<< anyway - it's loads easier.
    Away.

  4. #4
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    cin.getline(buffer_to_hold_input, num_of_chars, char_deliminator)

    If you are using the std::string, the function differs a bit.

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    Response

    Use cout<<" "; as has been said before.

    Example of <<endl;

    cout<<"this is a string."<<endl; //this creates a new line.

    Escape sequences are also allowed as shown.

    cout<<"\tthis is a string.\n";

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    Lack of CLarity

    Im sorry, I should have said. (string variable)
    the only way I can print out the charectors in a string at the moment is.......

    for(x=0;x<sizeofstring;x++){
    cout << string[x];
    }


    this becomes, tedious, and Im sure that there is a command that will allow me to print the string en masse. I appologize for my lack of clarity, I do know the basics of C, and, what little I derived from a high school class, C++.
    Last edited by parrellel; 07-06-2003 at 10:09 AM.

  7. #7
    Registered User Casey's Avatar
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    If you're using the string class from <string> then cout will work. If you're using a nul terminated array of char, then cout will still work. If you're using some user defined class that doesn't overload operator<< then cout won't work. Can you show us the string variable declaration?

  8. #8
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    Why are you iterating through the string? You're not changing variables. As has been said before you don't need to do it that way, just do this cout<<string; and the whole string will be outputed to the console window.

  9. #9
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    output is not the string by writing

    cout << array;

    output is a memory address. This is what you instruct me to do? Accessing the memory address, expectedly, offers me the first peice'o'array not the area en tota.

    Or am I being horribly stupid.

  10. #10
    Registered User Casey's Avatar
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    Can you post your code already? You've given us useless little snippets so far, we need more to figure out what your exact problem is.

  11. #11
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    Yes, we need code. At this point I'm assuming your using std::string from when you said string variable. But it could be a char array. Post the code, and we'll be able to help you more.

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