Thread: problems converting string to char[]

  1. #1
    Registered User
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    Oct 2002
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    problems converting string to char[]

    Hello!

    i searched the forum for string to char posts and tried a good one for converting a string to char[]:

    Code:
    string mystring = "that this and those"; 
    char  mychar[mystring.length()] = "";
    
    for (int i=0; i < mystring.length(); i++)
      mychar[i] = mystring[i];
    
    cout << mychar;
    It gives the right output but appends some weired output and i dont know how to fix it. I also tried to use:

    Code:
    for (int i = 0; i < mystring.length();++i )
    But doesnt work either. There is still this weired appended output.



    Thanks in advance!

    ~Jan

  2. #2
    It's full of stars adrianxw's Avatar
    Join Date
    Aug 2001
    Posts
    4,829
    Set the size of the char array to 1 larger than the CString. You need a NULL on the end to terminate the string. The rubbish you are seeing is whatever happens to be in memory after the end of the characters you are copying.
    Wave upon wave of demented avengers march cheerfully out of obscurity unto the dream.

  3. #3
    Registered User
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    Jan 2003
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    648
    You could always:
    Code:
    string mystring = "that this and those"; 
    char  mychar[mystring.length() + 1];  // allow space for null
    
    strcpy(mychar, mystring.c_str());  // copy the string's data into your c-string

  4. #4
    Registered User
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    Jan 2003
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    648
    Yea, I was being stupid. Just to show, I left two spaces between char and mychar, probably for the * for the new clause. STUPID ME! lol

  5. #5
    Registered User
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    Jul 2003
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    17
    Jan79 wasn't dynamically allocating memory. Jan was using the string class.

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