Loop

Is there any way not to exit a loop until I finsh all the index in that certain loop befor I go to the other one, example I have this code:
[cod]

#include<iostream>
#include <climits>

using namespace std;


int main(){

int c,i,r;
int b[3][1][5]={{0,1,2},{0},{0,1,2,3,4}};


for (c=0;c<5;c++){


r=0;

for( i=0;i<3;i++){// Here I do not want to exit this loop until I go three times on" i"


cout<<b[i][r][c]<<endl;

}

}


return 0;

}


[/code]


To be clearer I want my loop to show [0][0][0] not exit the "i" loop and show[1][0][0]then [2][0][0] after this one it exit and goes to the other loop and becomes[0][0][1],[1][0][1],[2][0][1]and now exit again and so on so in every time the last index is not change unless the loop turn three times.I appreciate the reply and the help.

So you are wanting to output the indices not the contents of b right? Because you talk about [0][0][1] and such but yet you are indexing into the b array in your example. I tweaked your code to get it to display the indices. Is this what you intended?

Code:

#include<iostream>
#include <climits>

using namespace std;


int main() {

  int c,i,r;
  int b[3][1][5]={{0,1,2},{0},{0,1,2,3,4}};

  r = 0;

  for (c=0;c<3;c++) {    
    for( i=0;i<5;i++) {
      cout<< c << r << i << endl;
    }
    cout << endl;
  }

  return 0;
}

I switched the order of your for loops for starters and then just displayed the index variables.

Thank you for the reply first. I do not want just to show the index. but I have a 3 dim array and I want to fill it in the following order [0][0][0],[1][0][0],[2][0][0]
[0][0][1],[1][0][1],[2][0][1]
[0][0][2],[1][0][2],[2][0][2]
[0][0][3],[1][0][3],[2][0][3]
[0][0][4],[1][0][4],[2][0][4]

as you can see this array has 3 raws and 1 raw and 5 columns.
so I want to fill the first 3 rows from each colums before I move to second one I hope I'm not confusing you, just let me know if you need more clarification. I want just to grab the idea of how to read the loop three times without changing the last 2 indices in every time of loop. Thanks.

Oh I think I see now. So you want to fill them in as such:

000
001
002

100
101
102

.
.
.

Right? Well then your loop is correct. All you need to do is assign values to the array. To prove the output is correct try making your for loop this:

Code:

  for (c=0;c<5;c++){
    for( i=0;i<3;i++){// Here I do not want to exit this loop until I go three times on" i"
      cout<< i << r << c << " "; 
    }

    cout << endl;
  }

If this still is not what you mean, then I'm confused. Let me know.

YES you are very very close. I did like the loop you posted but it gave different result. I will tell you what I want and ver easier way:

when c is = 0
then i is =012

when c is 1 then
i is 012
c is 2
is is 012
and so on

and I did this loop
[/cod]

for (c=0;c<5;c++){


r=0;

for( i=0;i<3;i++){


cout<<b[i][r][c]<<endl;
}



}
[/code]

but it gave differen result like this:000,101,202,003,004

and what I wanted is 000,100,200
001,101,201
002,102,202
and so on so you see the last one is changing only every 3 times. Thank you very much for trying to help.

Hey MrWizard
you are very right I checked your code and it is exactly what I wanted but the problem here is I need to fill those index in the same order.is that possible? I do not know why when I try to show them usingb[i][r][c] the do not appear like the same way when I use cout<<i<<r<<c;.Thanks.

Originally posted by Absy
Hey MrWizard
you are very right I checked your code and it is exactly what I wanted but the problem here is I need to fill those index in the same order.is that possible? I do not know why when I try to show them usingb[i][r][c] the do not appear like the same way when I use cout<<i<<r<<c;.Thanks.

*sighs*

Something like this???

Code:

#include <iostream>
using namespace std;

void FillArray( int A[3][1][5] )
{
  int i, r = 0, c, num = 0;

  for (c=0;c<5;c++){
    for( i=0;i<3;i++){
      A[i][r][c] = num++;
    }
  }
}

void DisplayArray( int A[3][1][5] )
{
  int i, r = 0, c;

  cout << "Values in the array:" << endl;

  for (c=0;c<5;c++){
    for( i=0;i<3;i++){
      cout << A[i][r][c] << " ";
    }

    cout << endl;
  }
}

int main( void )
{
  int b[3][1][5];
  
  FillArray( b );
  DisplayArray( b );

  return 0;
}