allocating memory for char* array

A few questions.

I know how to allocate memory for say 5 words that contain 10 characters each.
say:

char* wrdArray[5];

for (int count = 0; count < 5; count ++)
{
wrdArray[count] = new char[10];
}

strcpy(wrdArray[0], "Here is the first string.");
cout << wrdArray[0];
..
.. etc.


but how can i allocate memory/is it possible? for predefined words
that are of different lengths

using:
char** wrd = { "..", ".. " }; // can i use this ?? how ??

char* wrd[5] = { "these", "words", " need", "memory", "???" };

if in the second case, do i have to allocate memory?, how would i go about it?, do i have to use a for loop and allocate memory individually, can i do a group allocate/deallocate?
such as:
free(wrd);

any ideas would be great.

thanks.

Code:

char* wrdArray[5];

for (int count = 0; count < 5; count ++)
{
    wrdArray[count] = new char[10];
}

strcpy(wrdArray[0], "Here is the first string."); //Bufferoverflow

Code:

char* wrd[5] = { "these", "words", " need", "memory", "???" };

There is a const missing.

Code:

const char* wrd[5] = { "these", "words", " need", "memory", "???" };

Fine.Now you have an array of 5 constant char pointer,with memory allocated by the compiler,so don't call free on it.

You can copy the array

Code:

char *myWrds[5];
for(int i = 0;i < 5;i++)
{
    myWords[i] = new char[strlen(wrd[i]) + 1];
    strcpy(myWrds[i],wrd[i]);
}

thanks, that has it alot clearer