Why isn't this example working?

I copied this example from the book and no matter what i input the output memory address is always: 18495548

Enter last name: Fredeldumpkin
Fredeldumpkin at 18495548
Enter last name: Pook
Pook at 18495548

Instead of:

Enter last name: Fredeldumpkin
Fredeldumpkin at 0x004326b8
Enter last name: Pook
Pook at 0x004301c8

Code:

#include <clx.h>
#include <iostream>
#include <cstring>
#pragma hdrstop
//---------------------------------------------------------------------------
#pragma argsused
using namespace std;
char * getname(void);
int main(int argc, char* argv[])
{
        char * name;
        name = getname();
        cout << name << " at " << (int *) name << "\n";
        delete [] name;

        name = getname();
        cout << name << " at " << (int *) name << "\n";
        delete [] name;
        cin.get();
        cin.get();
        return 0;
}
char * getname()
{
        char temp[80];
        cout << "Enter last name: ";
        cin >> temp;
        char * pn = new char[strlen(temp) + 1];
        strcpy(pn, temp);
        return pn;
}

Try:

cout << name << " at " << ios::hex << (void *) name << "\n";

That made both of the memory addresses 1618495548

Why should they be different? You allocate the first piece of memory available, then free it, so next time you allocate, it is quite reasonable it will allocate the same address.

I read a book that referred to the addresses in hex form, yet from my 486 to my 1.8Ghz Pentium 4 I've yet to recieve a hex value when I print out the address. If it's not that big of a deal that it's not in hex I wouldn't worry about it.

Cool, i didn't think it was working because the addresses in the book were in hex and different... but if you guys say its working, then i'll take your word for it