Thread: Why isn't this example working?

I copied this example from the book and no matter what i input the output memory address is always: 18495548

Enter last name: Fredeldumpkin
Fredeldumpkin at 18495548
Enter last name: Pook
Pook at 18495548

Instead of:

Enter last name: Fredeldumpkin
Fredeldumpkin at 0x004326b8
Enter last name: Pook
Pook at 0x004301c8

Code:

#include <clx.h>
#include <iostream>
#include <cstring>
#pragma hdrstop
//---------------------------------------------------------------------------
#pragma argsused
using namespace std;
char * getname(void);
int main(int argc, char* argv[])
{
        char * name;
        name = getname();
        cout << name << " at " << (int *) name << "\n";
        delete [] name;

        name = getname();
        cout << name << " at " << (int *) name << "\n";
        delete [] name;
        cin.get();
        cin.get();
        return 0;
}
char * getname()
{
        char temp[80];
        cout << "Enter last name: ";
        cin >> temp;
        char * pn = new char[strlen(temp) + 1];
        strcpy(pn, temp);
        return pn;
}

Try:

cout << name << " at " << ios::hex << (void *) name << "\n";

That made both of the memory addresses 1618495548

I read a book that referred to the addresses in hex form, yet from my 486 to my 1.8Ghz Pentium 4 I've yet to recieve a hex value when I print out the address. If it's not that big of a deal that it's not in hex I wouldn't worry about it.

Cool, i didn't think it was working because the addresses in the book were in hex and different... but if you guys say its working, then i'll take your word for it