I want to overload pretty much every operator possible... however, I have to have two overloads, like this:
Since I plan on overloading close to 50... is there a way I can make the amount of code way less?PHP Code:template <typename UnknownType>
any operator +(const any & lhs, const UnknownType & rhs)
{
any result;
if (lhs.type() == typeid(UnknownType)) // check that types are same.
// no support for compatible but not same,
// sorry. Too much work to check for
// int and float, etc.
result = any_cast<UnknownType>(lhs) + rhs;
return result; // returns a copy of result
}
template <typename UnknownType>
UnknownType operator +(const UnknownType & lhs, const any & rhs)
{
UnknownType result;
if (rhs.type() == typeid(UnknownType)) // check that types are same.
// no support for compatible but not same,
// sorry. Too much work to check for
// int and float, etc.
result = lhs + any_cast<UnknownType>(rhs);
return result; // returns a copy of result
}
The body of each type would be identical, just the name of the overload (that includes type) would be different.
So if the overloads where the any comes first and the ones where it comes second... is there any way to do this without having 100 overloads at 8 lines of code?
