Bit manipulation

This is a discussion on Bit manipulation within the C++ Programming forums, part of the General Programming Boards category; can anyone please tell me how to return a bit for this problem address variable size is 3 i.e 001 ...

  1. #1
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    Bit manipulation

    can anyone please tell me how to return a bit for this problem
    address variable size is 3 i.e 001 or 110 then it has to generate the corresponding bit from a 8 bit vector11111111 corresponding to the address bit

    eg
    address is 101
    vector is 10101100
    101 is 5 so it should return 5th bit i.e 0 in this case


    void main()
    {
    const unsigned uN = 3;
    const unsigned u2_to_N = 2 * 2 * 2;

    CBooleanDataset MultiplexerDataset(uN + u2_to_N);

    CColumnVector<bool> InputVector(uN + u2_to_N);
    bool bOutput;
    for(unsigned i = 0; i <= u2_to_N; i++)
    {

    the thing is later i would later should be able to increase n for bigger problems

  2. #2
    Hardware Engineer
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    I'm not sure I understand the assignment, but to check bit-n, you can initialize your "mask" variable to one, and then bit-shift-left n-1 positions.

    Then, perform a bitwise-AND to test the unknown bit. If the result is zero, your unknown bit is zero.

    Bits are counted right to left, starting with bit zero which has a value (wieght) of 1. The "5th" bit would be bit-4. You'll be ANDing with 16 (base 10) or 0001 0000 (binary). So if you are testing bit-4, your mask is 16.

    This all gets bit more difficult if your input is actually in binary. If your input is hex or decimal, and you never have to "see" the binary format, it's much easier.

    P.S. You forgot to use code tags. Look above where it says "Posting Code? Read This First!"

  3. #3
    End Of Line Hammer's Avatar
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    There's some bit shifting notes here that may help you.
    When all else fails, read the instructions.
    If you're posting code, use code tags: [code] /* insert code here */ [/code]

  4. #4
    Disturbed Boy gustavosserra's Avatar
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    bitset?????

    I didnīt understand your problem very well, but remember that you always can use the C++ template bitset . I donīt know if this solve your problem... if you donīt know how to use bitfield, I attached the entire Borlandīs documentation for bitset.
    Attached Files Attached Files
    Nothing more to tell about me...
    Happy day =)

  5. #5
    Confused Magos's Avatar
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    Code:
    bool GetNthBit(char Flags, int N)
    {
       if(Flags & (1 << N)) return true;
       else return false;
    }
    N is an integer value 0 - 7. Of course you can change char to something else, say int and make N 0 - 31.
    MagosX.com

    Give a man a fish and you feed him for a day.
    Teach a man to fish and you feed him for a lifetime.

  6. #6
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    Thanks magos
    I am replying to my own problem and open to any more new ideas
    .i have got some idea
    if speed is very important then i could make it do something like this:
    create an array
    unsigned int *p = {0x01,0x02,0x04,0x08,0x10,0x20,0x40,0x80}

    and the function now becomes
    bool GetNthBit(char Flags, int N)
    {
    if(Flags & *(p+N) ) return true;
    else return false;
    }

    which may be faster because no shifts are required.

    and i could remove the need for the function and do it inline because in C and C++ zero is false and non-zero is true so this would then
    reduce to:
    (Flags & *(p+N)

    removing the need for an if test

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