What's it that I am doing wrong?

I am trying to change value of a variable by sending pointe to that variable as argument but I still get the same value in main(). What is it that I am doing wrong? Thanks a lot

#include <iostream.h>
#include <conio.h>
#include <string.h>
#include <stdio.h>


void modify(int *);

void main()
{
clrscr();
int num = 0;
int *aptr = &num;
modify(aptr);
cout << "Value of num is: " << num;

getch();

}

void modify(int *Num)
{
*Num = 10;


}

Use code tags please

And read about void main

However, your pointer usage looks OK. The program prints "Value of num is: 10" as you'd expect.

Since you are using C++, you may as well use a reference:

Code:

---

#include <iostream.h>

void foo( signed short int &bar )
{
    bar = 10;
    cout << "foo:bar is " << bar << endl;
}

int main( void )
{
    signed short int bar(0);

    foo( bar );

    cout << "main:bar is" << bar << endl;

    return 0;
}

---

For basic stuff like this, pointers are pretty much useless in C++, with the addition of references.

Quzah.

I am sorry, actually I made a mistake in the post. Function modify() looks like this:

void modify(int *Num)
{

*Num++;

}

Now, shouldn't this print 1 instead of the original value, which was zero?

>>*Num++;
This increments the pointer, not what it's pointing to. Use this instead:
>>(*Num)++;