how to return more then one value in a function?

This is a discussion on how to return more then one value in a function? within the C++ Programming forums, part of the General Programming Boards category; i know that each function can only return one value like integer or string, but if i have a function ...

  1. #1
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    how to return more then one value in a function?

    i know that each function can only return one value like integer or string,
    but if i have a function to process data but i want to return astring and an integer, how to do it?

    i am thinking of making a class....but....can a second function get any variable return in function 1?
    e.g

    funtion1 :

    c= a+b;
    d= c+50;
    return d;

    function2 :

    return c;

    can it be done if all the variable is define in the class as public variable?

    please help....thank you!

  2. #2
    pronounced 'fib' FillYourBrain's Avatar
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    you can "return" things via pointers and references.

    for instance:

    int Func(char *buffer, int & somethingelse)
    {
    somethingelse = 10;
    strcpy(buffer, "blah");
    return strlen(buffer);
    }

    somethingelse, buffer, and the return value are all going to be accessable after the function call
    "You are stupid! You are stupid! Oh, and don't forget, you are STUPID!" - Dexter

  3. #3
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    do you mean i dun need to define a class?

    see the example code first...
    Code:
    int function1()
    {
    int a = 2;
    int b = 3;
    c= a+b;
    d=b-a;
    return d;
    }
    
    int function2(int x)
    {
       return x+2;
    }
    do you mean that i can do the following in the int main()??
    Code:
    int main()
    {
    
    int m,n;
    m = function1;
    n = function2(c);
    
    return 0;
    }

  4. #4
    pronounced 'fib' FillYourBrain's Avatar
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    I'm not sure what you're asking. I thought you wanted to know how to make a function return more than one value.
    "You are stupid! You are stupid! Oh, and don't forget, you are STUPID!" - Dexter

  5. #5
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    2,662
    Code:
    int function1()
    {
       int a = 2;
       int b = 3;
       c= a+b;
       d=b-a;
       return d;
    }
    First of all, where did the variables c and d come from? They're not parameters to function1, and you didn't declare them in the function, so function1() won't even compile.

    Since it would only take 3 minutes to test whether you can do the things you want to do with the above function--why don't you?

    (Hint: you need to learn about passing-by-value and passing-by-reference.)
    Last edited by 7stud; 05-02-2003 at 02:56 PM.

  6. #6
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    sorry for typing the code wrongly

    mmmm....i think i know what you mean fillyourbrain.

    and i will try that out~~~

    thank you all~~~~

  7. #7
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    you could use a struct, but chances are, thats not what you want.

    Code:
    struct testing
    {
        int x;
        float y;
    };
    
    testing maketest(int x, float y)
    {
         testing test1;
         test1.x = y;
         test1.y = x;
         return test1;
    }
    
    #include <iostream.h>
    
    int main()
    {
         int number = 500;
         float decimal = 2.4;
    
         testing test1 = maketest(number,decimal);
         // should swap the two variables... rounding the decimal
    
         cout << test1.x << endl << test1.y << endl;
    
         return 0;
    }
    Last edited by Trauts; 05-02-2003 at 08:01 PM.

  8. #8
    ATH0 quzah's Avatar
    Join Date
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    Posts
    14,826
    Code:
    int returnmany( void )
    {
        return 1,2,3,4,5,6,7;/*;)*/
    }


    Quzah.
    Hope is the first step on the road to disappointment.

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