find no of even factor, express as %

question: enter a number, find number of even factor and expressed as percentage

i have type in the code and compiled it sucessfully. But the reuslt wasn't expected (always come as 0). Can someone please help to solve the problem. I am using a blood shed dev cpp ver 4.01.
Here is my code

Code:

int c(int day)
//find the even factor of day and expressed as percentage
//pre: day>0
//post: return percentage
{
 int eFactor;//even factor
 int tFactor;//total factor
 int i;//control variable
 int percent;//express as percentage
 
 //initialization
 eFactor = 0;
 tFactor = 0;

 for (i=1; i<=num; i++)
 {
  if (num%i==0)
  {
   tFactor++;
   if (i%2==0)
      eFactor++;
  }//end if  
 }//end loop

 percent = (eFactor / tFactor)* 100;
 return percent;
}//end c

Also the if-clause

Code:

if (num%i==0)

is not neccesary.

Your function should return a double or a float and not an integer number.

As a minor point, the number of even factors will be equal to the number of times you can divide by 2.

Code:

int num_even(int n) {
    int num=0;
    while(n>1 && n%2==0) {++num;n/=2;}
    return num;
}

int num_odd(int n) {
     n >>= num_even(n);
     int num=0;
     const int lim = ceil(sqrt(n));
     for(int d=3;n>1 && d<=lim;d+=2) {
         while(n%d==0) {
             ++num;
             n/=d; 
         }
    }
    return num;
}

also consider what happens with your loop on 12 (3*2*2) this should be 66% but yours(fixing round off) will return 50%