question on methods

[jimothygu]

Hiya,

I was wondering if anyone else could give me some input on what would be the best way to search a string for some values, and then print it out.

Suppose I have a string like: ">From: me To: you Subject: fun! Message: I hope you're having fun and all Time: Fri Apr 11 17:57:16 2003"

First I want to search the string for who it's from, and the subject. I've been using string.find(">From") and then another .find() to get the end of the sender's name. Then I make a .substr() with those values. Then I do that again for the subject.

so like:

   From                  Subject
-----------------------------------
1. Me                   fun!
2. Me                   C++ is cool!

I've also been trying to store those values in a vector, because eventually, there will be several strings like this, and I'd like to keep them organized. I will also eventually be viewing or deleting the whole message, so I thought storing the values in a vector might be easy. Anyway, I just wanted to know if anyone else had any ideas that might simplify this process. Thanks!

Jim

[kuphryn]

One solution is to search for key words such as "From: " and "To: ."

Kuphryn

[jimothygu]

Yeah, that's what I'm doing now. I search for From and the subject, and then put those in a vector. I am currently having trouble with a way of finding the next occurance of From and Subject, and so-on and so-forth. I was thinking of putting it in a for() loop, but I haven't had any luck with that yet.

cheers,

Jim

[alpha]

do you have a vector of strings? if so, then try searching through vect[i] in a for loop; maybe having another temp vector of strings for storing substrings.

[kuphryn]

One solution is a while loop and the last position.

size_t nFind = theMsg.find("From: ");
if (nFind != theMsg.npos)
{
...
// First position of valid data.
nFind += 6;
}
else
nFind = 0;

nFind = theMessage.find("To: ", nFind);
...

As you can see, the algorithm is very simply. I recommend one function for each key word search. That will help organize your code.

Kuphryn

[jimothygu]

I've been trying various methods, but none of them is giving me the output I want, or it terminates the program because of an error.
This is what I have so far:

string ms;
int s1, f1, hold, f2hold, f1hold, length, i=0;
string f2, s2;

ms = ">From: Jim\nTo: Lauren\nSubject: Zoo\nMessage: I was just wondering if you were going to the zoo today.  
Gimmie an email please. \nTime: Sat Apr 12 11:32:09 2003>From: Lem\nTo: Jim\nSubject: Re:Zoo\n
Message: Nah, not going today.  \nTime: Sat Apr 12 11:32:09 2003";  
// string is all one line

while(ms.find("From:")){
    length = ms.size();
    f1 = ms.find("From:");
    hold = ms.find("\nTo:");
    f1hold = hold - f1;
    f2.assign( ms, f1, f1hold);

    s1 = ms.find("Subject");
    hold = ms.find("\nMessage:");
    f2hold = hold - s1;
    s2.assign( ms, s1, f2hold);
    cout << ++i << ": " << f2 << "     " << s2 << endl;;
       ms.erase (hold, length);
             }

What I want it to do is search for the From and Subject, print it out, then delete the section it's already checked, and begin the process again.
So I want the output to be:

1. From: Jim Subject: Zoo
2. From: Lem Subject: Re:Zoo

I tried the .npos method, but I wasn't able to make it work.

cheers,

Jim