Help on The Towers of Hanoi

HI!!!!
I need some help on this program. I really don't know where I am...If I am very far for what I want or I am close, right now I am getting some error on the Solve function where I try to do this: Source.push_back(Destination.pop_back()); //Move from Source to Destination....................
The error says something about the function is declared void..like if I am trying to return something.....

If you have some hints for me or if you want to see how the output should look like, I have an executable file (for linux/unix system) that I can send to you. Right now I am programming it on Dev++ on Windows, later on I will paste it and everything on a linux system..Thanks for any help you can give to me

Code:

//Towers of Hanoi....

using namespace std;

#include <iostream>
#include <stdlib.h>
#include <vector>
#include <iomanip>
#include <string>
#include <cmath>

void header(int &argc, int i);
void show(int &argc, vector<int> &array1, vector<int> &array2, vector<int> &array3);
void waitForUser();
void Solve(int N, vector<int> &Source, vector<int> &Aux, vector<int> &Destination);
void init(int argc, vector<int> &array1);
void swap(int &N, vector<int> &Source, vector<int> &Destination);

int main(int argc, char *argv[])
{
  argc = 3;
  int steps = pow(2,argc)-1;
   vector<int> array1(argc);
   vector<int> array2(argc);
   vector<int> array3(argc);  
   
  
     for(int i = 0; i <= steps; i++){
         header(argc, i);
         init(argc, array1);
         Solve(argc, array1, array2, array3);
         show(argc, array1, array2, array3);
         waitForUser();
         //system("clear");
     }
    
  system("PAUSE");	
  return 0;
}
void header(int &argc, int i){
   cout << "**** HANOI TOWER ****" << endl;
   cout << "N=" << argc << setw(17) << "STEP " << i << endl;
}
void show(int &argc, vector<int> &array1, vector<int> &array2, vector<int> &array3){
     for(int j = 0; j < argc; j++){
          
        
        cout << setw(3) << array1[j] << setw(8) << array2[j] << setw(8) << array3[j] << endl;
  }
  cout << "=====   =====   =====\n";
  cout << "  A       B       C\n\n";
}
void waitForUser() {
  // waits for the user to hit <ENTER>
  string dummy;

  cout << "Press <ENTER>";
  getline(cin, dummy);
  cout << endl;
}
void Solve(int N, vector<int> &Source, vector<int> &Aux, vector<int> &Destination){
   for(int i = 0; i < N; i++){
     // while{N =! 0){
        Solve(N-1, Source, Destination, Aux);
        Source.push_back(Destination.pop_back());  //Move from Source to Destination
        Solve(N-1, Aux, Source, Destination);
     // }
    }
}
void init(int argc, vector<int> &array1){
   for(int j = 0; j < argc; j++)
       array1[j] = j+1;
}
void swap(int &N, vector<int> &Source, vector<int> &Destination){
   for(int i = 0; i < N; i++){
      Destination[i] = Source[i];
      //Source[i] = 0;
   }
}

pop_back() returns void...

gg

What means that pop_back() returns void????

>What means that pop_back() returns void????
It means it doesn't return a value, so

Code:

Source.push_back(Destination.pop_back());

will not work. Look up your reference for how to use pop_back.