passing a character array through a function

I keep getting conversion errors. What should I put as the return statement in the function definition?

Code:

#include <iostream>
using namespace std;

char capitalize(char []);

int main()
{
	char string[81];
	
	char c;
	
	cout << "Enter a sentence" << endl;
	cin.getline(string, 81);

	c = capitalize(string);

	cout << endl << c << endl;
	
	return 0;
}

char capitalize(char string[])

{
	register int i = 0;
	
	while (string[i++])
	{
		string[0] = toupper(string[0]);

		if (string[i] == ' ')
			string[i + 1] = toupper(string[i + 1]);
	}
	
	return string;
}

This is the only solution I can come up with, but I want the cout statement that displays the string to be in main() instead of the function definition of capitalize().

Code:

#include <iostream>
using namespace std;

void capitalize(char []);

int main()
{
	char string[81];
	
	cout << "Enter a sentence" << endl;
	cin.getline(string, 81);

	capitalize(string);

	return 0;
}

void capitalize(char string[])

{
	register int i = 0;
	
	while (string[i++])
	{
		string[0] = toupper(string[0]);

		if (string[i] == ' ')
			string[i + 1] = toupper(string[i + 1]);
	}
	
	cout << endl << string << endl;
}

Okay a made a few changes.

Code:

#include <iostream>
using namespace std;

char* capitalize(char []);

int main()
{
  char *lpString = NULL;
  char string[81];

  cout << "Enter a sentence" << endl;
  cin.getline(string, 81);

  lpString = capitalize(string);

  // Make sure our pointer is valid
  if( lpString != NULL )
    cout << lpString << endl;

  return 0;
}

char* capitalize(char string[])
{
  register int i = 0;

  while (string[i++])
  {
    string[0] = toupper(string[0]);

    if (string[i] == ' ')
      string[i + 1] = toupper(string[i + 1]);
  }

  return string;
}

Lets talk about your first implementation. That was really close except that in your capitalize function you were trying to return a single char. This should have given you an error when you were trying to return string at the end of the function. Something along the lines of unable to convert from char[] to char. Anyways, since we can't return an array from a function we need to return a pointer to it. That's what I have done in my function. Then you can either assign that pointer to the result and output it like that or if you don't need to save the pointer for later use you can simply do:

Code:

cout << capitalize( string ) << endl;

Hope this helped.

Thanks MrWizard. Oh yeah, you're that Digipen student...

Originally posted by volk
Thanks MrWizard. Oh yeah, you're that Digipen student...

??? What's that supposed to mean?

It means that of course you were able to easily solve that problem since you're a digipen student. Those students are supposedly very talented, right? You probably receive a very high level of training over there. Why else would that school be so frigin' expensive?