minimum numbers to be entered into an array

Is it possible to accept a minimum of ten numbers to be entered into an array? I know it's possible to accept a maximum of ten numbers to be entered into an array.

Is this where vectors come in?

dont let the loop leave until ten are taken

Code:

---

int somearray[10];

for (int i = 0; i < 10; i++)
{
cout << "Enter int: ";
cin >> somearray[i];
}

---

Quote:

---

Originally posted by RoD
dont let the loop leave until ten are taken

Code:

---

int somearray[10];

for (int i = 0; i < 10; i++)
{
cout << "Enter int: ";
cin >> somearray[i];
}

---

---

That code doesn't look like it scans for a minimum of ten numbers; it looks like it's scanning for exactly ten numbers. What if I want to enter eleven numbers?

I guess what I want is impossible to do with arrays...

Code:

---

for(int i=0; i<10; i++)
{
  cin >> Array[i];
}

int Temp;
int j = 10;
do
{
  cin >> temp;
  if(Temp != -1)
  {
      Array[j] = Temp;
      j++;
  }
}while(Temp != -1)

---

Assuming that the exit condition is the user enters -1.


EDIT:

Or even better:

Code:

---

int Temp;
int i = 0;

do
{
  cin >> Temp;
  if(Temp != -1)
  {
      Array[i] = Temp;
      i++;
  }
}while((Temp != -1) || (i < 10))

---

well, if you want to change the size, vectors come into play. you can use resize() if you need to.

or you could also use a linked list and dynamically allocate memory.