linked lists

This is a discussion on linked lists within the C++ Programming forums, part of the General Programming Boards category; i need to create a linked list of characters which i'll be retrieving from a text file. my problem is ...

  1. #1
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    linked lists

    i need to create a linked list of characters which i'll be retrieving from a text file. my problem is that i'll need to access this data in the same order that i retrieve it in. i am only used to writing linked lists so that it actually reverses the data using a stack. any ideas on this?

  2. #2
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    "i am only used to writing linked lists so that it actually reverses the data using a stack. any ideas on this?"

    Yep. Learn to write 'em so you can access the items in the list in any order. How about having data members of the list like:

    Node* pbeginning
    Node* pcurrent
    Node* pend
    Last edited by 7stud; 04-03-2003 at 12:08 AM.

  3. #3
    Veni Vidi Vice
    Join Date
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    Create a double linked list (DLL) and traverse it backwards.

  4. #4
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    "i am only used to writing linked lists so that it actually reverses the data using a stack. any ideas on this?"

    First lets straighten out your terminology. A stack and a linked list are two seperate data structures. I'll assume you are refering to a linear linked list. What you should use, is a circular linked list.

    If you need more information just post, I'm a bit tight on time.

  5. #5
    Open to suggestions Brighteyes's Avatar
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    You could learn how to add a new node at the end of a list instead of the beginning and save yourself a lot of trouble.
    Code:
    // Assuming a node like this
    struct node {
        int content;
        node *next;
    
        node(int c, node *n)
        {
            content = c;
            next = n;
        }
    };
    
    // Add at the front
    current = new node(data, front);
    front = current;
    
    // Add at the end
    if (front != 0)
    {
        for (current = front; current != 0; current = current->next)
        {
            if (current->next == 0)
                break; // Found the end
        }
    
        current->next = new node(data, 0);
    }
    else
        front = new node(data, 0); // Empty list

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