Increamenting Array Adresses

Hi, i'm working with pointers and references and wanted to try out a simple program with an array. One variable will store the adresse of the first element in the array, than - the array will be increamented to the next element, and thus will reassign the new adress to a variable. I thought this would be simple but, well its not =/.

Code:

#include <iostream.h>
#include <stdlib.h>
int main() {
double a[100];
double *pVar; //create pointer to variable
pVar = &a[000]; //store adresse in pVar

   do {         //reiterate through untill done
     if (&a[001] < &a[099], ++&a[000]) {  //check if adresse of a[001] is less than next in array...
              pVar = &++a[001]; //assign new adresse to pVar
              cout << "adresse of a[???] = " << pVar; } //print new adress

              else {  //when done...
                   cout << "done";
                   system("PAUSE"); }
                                    while(1); //loop while

                                    return(0); //return 0 to exit
                                    }
}

It is supposed to print the adresses of 99 array elements consecutavily. I'm not profficient in memory adresses so, please excuse me if this is a silly error...

For starters you aren't actually doing what you think you're doing. If what you want to do is cycle through each element of the array and assign it's address to another variable then a much cleaner way (since you know the size of the array before hand) would be like this:

Code:

#include <iostream>
using std::cout;
usind std::endl;

int main() 
{
	double a[100];
	double *pVar; //create pointer to variable
	
	for(int i=0;i<100;i++)
	{
		pVar=&a[i];
		cout<<"address = "<<pVar<<endl;
	}
	cout<<"done"<<endl;
	return(0); //return 0 to exit
}

Notice that I used the new standard iostream header, etc. You were also including stdlib.h even though you didn't need it.

Also, why were you referencing elements with triple digits; ie: a[000], etc.?