Thread: graphs

i am trying this exercise and i dont know wot 2 do!

Graphs are usually shown with the X axis as a horizontal and the Y axis as a vertical. As you will only be allowed to use a one-dimensional array in this coursework, the usual X and Y axis will need to be swapped around. Write a program that displays the graph of the following equation Y=2X+5 The program should first ask the user for:1. the X axis starting point 2. the number of steps3. step-sizeIt should then repeatedly calculate the value of Y using the changing value of X. Normally, X increases by the step size for the number of steps specified. The program should display an ‘*’ in each X column to denote the Y value, e.g. if Y = 10, then the 10th element of an 81 element character array should be set to ‘*’ and then the string Graphs are usually shown with the X axis as a horizontal and the Y axis as a vertical. As you will only be allowed to use a one-dimensional array in this coursework, the usual X and Y axis will need to be swapped around.

Write a program that displays the graph of the following equation

Y=2X+5

The program should first ask the user for:

1. the X axis starting point
2. the number of steps
3. step-size

It should then repeatedly calculate the value of Y using the changing value of X. Normally, X increases by the step size for the number of steps specified. The program should display an ‘*’ in each X column to denote the Y value, e.g. if Y = 10, then the 10th element of an 81 element character array should be set to ‘*’ and then the string

this is wot ive done

#include <stdio.h>
#include <stdlib.h>
#include <conio.h>

#define GRAPH_SIZE 80

main ()
{

int x;
int y;
int increment = 1;
int counter;
int steps;
int size;
char graph[GRAPH_SIZE];
int counter2;

printf ("Starting point of X Axis: ");
scanf("%d", &x);

printf ("Number of Steps: ");
scanf("%d", &steps);

printf ("Step Size: ");
scanf("%d", &size);


printf("--------------------------------------------------------------------------------");

for(counter = 0 * size; counter < steps * size ; counter+= size)
{
y = (2 * x) + 5;


for (counter2 = 0; counter2 <=80; counter2 ++)
{


if (counter2 == y)
graph[counter2] = '*';
else
if (counter2 != y)
graph[counter2] = ' ';
if (y < 0)
graph[0] = '0';
else
graph[0] = '|';

}
printf("%s", graph);
}

getch();

return(0);


}


the problem is that the graph appears the axis on the left is indented, having a problem insertin the "+" sign.