Thread: Array won't display new values?

  1. #1
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    Array won't display new values?

    I'm trying to make a simple tic-tac-toe program. In the example below, it's incomplete, only I finished it enough to run it and check for errors.
    Code:
    #include <iostream.h>
    #include <stdio.h>
    #include <time.h>
    
    char playagain='y';
    int number;
    char array[10];
    int main(void)
    {
    	array[1]='1';
    	array[2]='2';
    	array[3]='3';
    	array[4]='4';
    	array[5]='5';
    	array[6]='6';
    	array[7]='7';
    	array[8]='8';
    	array[9]='9';
    	while(playagain=='y')
    	{
    	cout << array[1];
    	cout << "|";
    	cout << array[2];
    	cout << "|";
    	cout << array[3];
    	cout << "\n-----\n";
    	cout << array[4];
    	cout << "|";
    	cout << array[5];
    	cout << "|";
    	cout << array[6];
    	cout << "\n-----\n";
    	cout << array[7];
    	cout << "|";
    	cout << array[8];
    	cout << "|";
    	cout << array[9];
    	cout << "\n";
    	cout << "Please enter the number of the space you would like to place an X in: ";
    	cin >> number;
    	for(int i=1;i<10;i++)
    	{
    	if(number==array[i])
    	{
    	array[i]='X';
    	}
    	}
    	}
    	return 0;
    }
    When I run it, no matter what number I put in, it always displays array[i] (i being whatever number I put in), as the number it originally was, not 'X', as it should be. As you can see, I declare the array numbers outside of while(playagain=='y'), so it shouldn't redefine them after looping. Please help.

  2. #2
    Registered User Codeplug's Avatar
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    Hint:
    Code:
    char c = '1';
    int n = 1;
    if (c != n)
       cout << "This line will be executed always!" << endl;
    gg

  3. #3
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    I see. So, how can I make this work? I don't want to use multiple variables for each space...Can I convert a char into an int temporarily?

  4. #4
    Registered User Codeplug's Avatar
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    Quickest solution:
    Code:
    int number; ==> char number;
    gg

  5. #5
    Registered User Vber's Avatar
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    array[1]='1';
    array[2]='2';
    array[3]='3';
    array[4]='4';
    array[5]='5';
    array[6]='6';
    array[7]='7';
    array[8]='8';
    array[9]='9';
    Why don't you use a loop, instead writing all this? ahh and one thing, arrays are from 0 to N-1, and not from 1 to N-1. About changing the type of a variable temporary, search for casting, well, I don't know C++, but in C it goes like this:

    Code:
    (typeName) varName;
    this forces varName to be of typeName.
    Last edited by Vber; 03-17-2003 at 06:10 AM.

  6. #6
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    I know, but if i=0, that elimintes some much easier coding later on

  7. #7
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    declare number as a char...

  8. #8
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    Yeah, I tried that, but number as a char didn't accept input properly. Anyway, I found somewhere on this board that char i='4', i=i-'0' makes i integer 4.

  9. #9
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    Code:
    #include <iostream.h>
    #include <stdio.h>
    #include <time.h>
    
    char playagain='y';
    char number;
    char array[10];
    int main(void)
    {
    	array[1]='1';
    	array[2]='2';
    	array[3]='3';
    	array[4]='4';
    	array[5]='5';
    	array[6]='6';
    	array[7]='7';
    	array[8]='8';
    	array[9]='9';
    
    	while(playagain=='y')
    	{
    		for (int i = 1; i < 10; i++)
    		{
    			if (i % 3 != 0)
    				cout << array[i] << "|";
    			
    			else 
    				cout << array[i] << "\n-----\n";
    		}
    
    	cout << "\nPlease enter the number of the space you would like to place an X in: ";
    	cin >> number;
    
    	cout << endl;
    
    	for(i=1;i<10;i++)
    	{
    	if(number==array[i])
    	{
    	array[i]='X';
    	}
    	}
    	}
    	return 0;
    }
    I tried that in 3 diff compilers and it worked....Also, cleaned it up alittle.

  10. #10
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    Alright, well, that part's working, now. Please see my other thread if you're interested in helping me with my other problem.

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