Array won't display new values?

I'm trying to make a simple tic-tac-toe program. In the example below, it's incomplete, only I finished it enough to run it and check for errors.

Code:

#include <iostream.h>
#include <stdio.h>
#include <time.h>

char playagain='y';
int number;
char array[10];
int main(void)
{
	array[1]='1';
	array[2]='2';
	array[3]='3';
	array[4]='4';
	array[5]='5';
	array[6]='6';
	array[7]='7';
	array[8]='8';
	array[9]='9';
	while(playagain=='y')
	{
	cout << array[1];
	cout << "|";
	cout << array[2];
	cout << "|";
	cout << array[3];
	cout << "\n-----\n";
	cout << array[4];
	cout << "|";
	cout << array[5];
	cout << "|";
	cout << array[6];
	cout << "\n-----\n";
	cout << array[7];
	cout << "|";
	cout << array[8];
	cout << "|";
	cout << array[9];
	cout << "\n";
	cout << "Please enter the number of the space you would like to place an X in: ";
	cin >> number;
	for(int i=1;i<10;i++)
	{
	if(number==array[i])
	{
	array[i]='X';
	}
	}
	}
	return 0;
}

When I run it, no matter what number I put in, it always displays array[i] (i being whatever number I put in), as the number it originally was, not 'X', as it should be. As you can see, I declare the array numbers outside of while(playagain=='y'), so it shouldn't redefine them after looping. Please help.

Hint:

Code:

char c = '1';
int n = 1;
if (c != n)
   cout << "This line will be executed always!" << endl;

gg

I see. So, how can I make this work? I don't want to use multiple variables for each space...Can I convert a char into an int temporarily?

Quickest solution:

Code:

int number; ==> char number;

gg

array[1]='1';
array[2]='2';
array[3]='3';
array[4]='4';
array[5]='5';
array[6]='6';
array[7]='7';
array[8]='8';
array[9]='9';

Why don't you use a loop, instead writing all this? ahh and one thing, arrays are from 0 to N-1, and not from 1 to N-1. About changing the type of a variable temporary, search for casting, well, I don't know C++, but in C it goes like this:

Code:

(typeName) varName;

this forces varName to be of typeName.

I know, but if i=0, that elimintes some much easier coding later on

declare number as a char...

Yeah, I tried that, but number as a char didn't accept input properly. Anyway, I found somewhere on this board that char i='4', i=i-'0' makes i integer 4.

Code:

#include <iostream.h>
#include <stdio.h>
#include <time.h>

char playagain='y';
char number;
char array[10];
int main(void)
{
	array[1]='1';
	array[2]='2';
	array[3]='3';
	array[4]='4';
	array[5]='5';
	array[6]='6';
	array[7]='7';
	array[8]='8';
	array[9]='9';

	while(playagain=='y')
	{
		for (int i = 1; i < 10; i++)
		{
			if (i % 3 != 0)
				cout << array[i] << "|";
			
			else 
				cout << array[i] << "\n-----\n";
		}

	cout << "\nPlease enter the number of the space you would like to place an X in: ";
	cin >> number;

	cout << endl;

	for(i=1;i<10;i++)
	{
	if(number==array[i])
	{
	array[i]='X';
	}
	}
	}
	return 0;
}

I tried that in 3 diff compilers and it worked....Also, cleaned it up alittle.

Alright, well, that part's working, now. Please see my other thread if you're interested in helping me with my other problem.