Thread: Returning Entire Arrays

I was wondering if I was doing this correctly. Does this line of code:

Code:

main()
{
 siPlayerGrid[8][16][5] = setter(siPlayerGrid, siCompGrid, i, j);
}

setter(short siPlayerGrid, short siCompGrid, short i, short j)
{
 return siPlayerGrid[8][16][5];
}

Correctly return the whole array?

Thanks in advance.

Sorry, I meant this code:

Code:

main()
{
 siPlayerGrid[8][16][5] = setter(siPlayerGrid, siCompGrid, i, j);
}

setter(short siPlayerGrid[8][16][5], short siCompGrid[8][16][5], short i, short j)
{
 return siPlayerGrid[8][16][5];
}

It´s difficult to say. I can´t see anything wrong in your code, but nethier can I see anything usefull...

I'm just trying to ensure that it is returning the entire array, rather than just the values at those elements, (though the subsets are [0-7][[0-15][0-4]).

When called, it passes the values, when returning it passes the values!

It´s like this:

Code:

function(type passedbyvalue,type& passedbyreference);

The passedbyreference variable shouldn´t be returned though!

Using & would pass it as a pointer, how would I pass the arrays as a reference so I don't have to return them?

No, my friend, using & passes it as reference.
Using * passes it as pointer.

Try out this piece of code yourself:

Code:

#include <iostream>
using namespace std;

void add1(int& passedbyreference){
	passedbyreference++;
}
int main(int argc, char** argv){
	int i = 0;
	add1(i);
	cout << i << endl;
}

>how would I pass the arrays as a reference so I don't have to return them?


actually, arrays are always passed by reference, doesnt matter if you use & or not.

Really!? Great, this makes my program more efficient since it doesn't need so many memory allocations when I send arrays to functions!

Thanks!