Thread: Whats wrong with my array?

Code:

char board[3][3] = { "0.0", "0.1", "0.2", "1.0", "1.1", "1.2", "2.0", "2.1", "2.2" };

It seems like it is fine to me. But I am getting 102 errors in my code, most just complaining that I need an array to use it like that. The array brings up these errors-

board.h(16) : error C2059: syntax error : '{'
(16) : error C2334: unexpected token(s) preceding '{'; skipping apparent function body

EDIT: array's indention was skrewed so I just put it that way.

for one thing it should be char board[3][4] because you're storing a 3 element char + the null terminator.

A null terminator is '\0' which is added to the end of a char array. Also, you aren't declaring just 9 elements. If you want 9 char arrays that each hold a 4 element char arrays then you'll want this:

char board[9][4] = {stuff........etc};

This is what's happening: You are wanting to store 3 chars into an array (example: "0.0" is 3 because you have 2 "0"s and the period seperating them). You have to give enough room for the null terminator, so you need a 4 element char array.

Here's what it'll look like:

Code:

board[0]="0.0";
board[1]="0.1";
board[2]="0.2";
board[3]="1.0";
board[4]="1.1";
board[5]="1.2";
board[6]="2.0";
board[7]="2.1";
board[8]="2.2";

//so if you break it down, they'd look like this:
board[0][0]='0';
board[0][1]='.';
board[0][2]='0';
board[0][3]='\0';

board[1][0]='0';
board[1][1]='.';
board[1][2]='1';
board[1][3]='\0';

//etc etc

But why can't I declare my array like it is?

Originally posted by Munkey01
But why can't I declare my array like it is?

You can declare it like it is, but you can't dump that much data into the way it's declared. Just change it to:

Code:

char board[9][4] = { "0.0", "0.1", "0.2", "1.0", "1.1", "1.2", "2.0", "2.1", "2.2" };

If you insist on declaring it the way you have then you'll be restricted to what you can initialize it to. Like this:

Code:

char board[3][3] = {"0.", "1.", "2."};

The reason why is because of the basic semantics of the language. If you want to store X amount of information in an array then you need to declare the array to size X.

But it is still bringing up the same error... Saying that the braces are a syntax error.

You have 3 rows and 3 columns of 4 element arrays

You need:

char board[3][3][4] // init list;

or if you will not modify the contents you can use:

char *board[3][3] // init list;

Code:

#include <iostream>

int main(int argc, char *argv[])
{
	char board[3][3][4] = {{"0.0", "0.1", "0.2"}, {"1.0", "1.1", "1.2"}, {"2.0", "2.1", "2.2" }};
	for (int i=0; i<3; ++i)
	{
		for (int j=0; j<3; ++j)
			std::cout << board[i][j] << " ";
		std::cout << std::endl;
	}
	return 0;
}

Why do you have main() taking arguments? Anyways it is still bringing up the same error.

The declaration of main was inserted by my IDE. It is a legal declaration, but the args are not required by this little program.

Try pasting my code into a file and compile it. There is no way you should still get that same error.

Maybe if I change my code around to deal with an integer array instead maybe all of this confusing can be settled, hmmmm.

Try removing or replacing double qoutes to single or seperating the variables with just commas " , ". and jdinger may be right.
You need [9][4].

You are inputting as strings and may need the null terminator.

Keep getting problems. I even tried using an integer array instead of a character but I still come up with the same error.

I am not positive it is even declared correctly, but VC++6 keeps complaining about it.

Code:

int board[3][3] = {{"00", "01", "02"}, {"10", "11", "12"}, {"20", "21", "22"}};