could use a little help

**Gil22** · 02-24-2003

Just wondering if someone could help me with a problem i'm having, i have a class with member functions and a few variables. The program is supposed to do some calculations and then output something specific to the screen depending on what the input was. heres the problem, the only way i can output is by typing the following command in main

cout << "bluh bluh bluh is" << function() << endl;

i need to output an entire word but i cant figure out how to return a whole string instead of just a character, i believe it has something to do with pointers if that helps. i have tried to work this out on my own for hours and just cant seem to get anywhere. thanks in advance.

**Travis Dane** · 02-24-2003

You can char arrays wich hold entire words, But for beginners (
are you?) i recommend using the string class, Can't find a
tutorial right now so:

Code:

#include <string>

using namespace std;

string afunction()
{
return "hohoho";
}

int main()
{

cout << afunction() << endl;

return 0;
}

**Gil22** · 02-24-2003

thanks for the response, i tried that and still got an error message. it says something about no operator defined. i think its basically saying that I cant have a function of type string to the right of <<

some other things i didnt mention before are that the function i am using is a friend function of a class. it takes two arguments of the type of the class. example:
class example
......

main()
example ex1, ex2
cout <<"bluhhhhhhhh is" << function(ex1,ex2)

my questions are......can i use a string type for a function if its a
friend function and why might i still be getting that error message

**Travis Dane** · 02-24-2003

Could you post your entire code? I can't resolve an error with
no code...

**Gil22** · 02-24-2003

i emailed it to you if thats alright

**Travis Dane** · 02-24-2003

Problem is simple, Use <iostream> instead of <iostream.h>,
<iostream.h> is an old version.

**Gil22** · 02-24-2003

awsome.....works fine now. thanks for your help, it may have been simple but there was no way i was going to find that. that string type will def be coming in handy now.

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