How to Flush standard input?

Hi!

I´m trying to fulsh standard input - all though this seems not possible to me. My code is:

Code:

---

        bool exit_status;
        char current;

        exit_status=false;
        while(!exit_status){
                cin.clear();
                cin >> current;
                switch(current){
                case 'p':
                        // do something
                break;
                case 'u':
                        // do something
                break;
                case 's':
                        // do something
                break;
                default:
                cout << "Unkown command" << endl;
                }
}

---

When I run this, I don´t expect when typing: "pussy", that the program runs the functions ascossiated with p,u,s,s and types "Unkown command"....

Anyone knows how to flush the inputstream so that only function p will be run???

y not

char variable[1];

now only the first letter is read....and i hope u mean pussy in the feline sense.

Sure I could read the thing into a string, but what I search is a function that will FLUSH unread input. I thought clear(): did that, but it doesn´t... Any suggestions?

i used

cin.clear();
cin.ignore();

in my bot.

http://cboard.cprogramming.com/searc...der=descending

cin.clear() clears the flag that would be set if a user entered a character into an integer variable or such.

cin.ignore(80, '\n') *should* do what you want as it *should* strip off everything but your 'p'

Use the folowing code fragment..

Code:

---

void ClearStdInput()
{
  while(1)
  {
      if(kbhit())
        getch();
      else
        break;
  }
}

void main()
{
  ........
  .......
  ClearStdInput();  //Clears standard input.
  .......
  ........
}

---

Happy Hunting...

What about something like fflush()?

fflush fails to work sometimes on some compilers such as Turbo C++. The ClearStdInput() is foolproof.