> 1 5
> 2 5
> 3 5
Sheesh - what were you expecting???
Surely you must have realised by now that doing 100 * 0.05 will be 5 whether you do it once or 100 times.
Code:for (int i=1; i < years+1 ; ++i) { // does temp depend on the value of i - NO! // is temp going to change? - NO double temp = forest_rate * uncut_area; // what about this one then? area_forested = (uncut_area + temp * i); cout << i << " " << temp << endl; }
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
the formula ( uncut_area + (forest_rate * uncut_area)
using the numbers 10000 total area, 100 left uncut, .05 forest rate
u get 100 + (.05 * 100) which is 105 which equals how much will be left after 1 year
then 105 + (.05 *100) which is 110.25 is what is left after 2 yrs
then 110.25 + (.05*110.25) = 115.7625
an you continue until X number of years has passed ( years is the variable for years)
after 20 years have passed the answer is supposed to be like........635.33? i dont get it i get 105. then 110, then 115 without the decimals.........
werid to use a for loop i know.............i figured out i need some way to tell the lloop to take the number from each year an add it to the previous until X number of years has passed.........then output the answer as area_forested........
> u get 100 + (.05 * 100) which is 105 which equals how much will be left after 1 year
> then 105 + (.05 *100) which is 110.25 is what is left after 2 yrs
Surely you mean
> then 105 + (.05 *105) which is 110.25 is what is left after 2 yrs
If so, then like this
Then print the value of uncut_area at the end of the loop.Code:for (int i=1; i <= years ; ++i) { uncut_area = uncut_area + (forest_rate * uncut_area); }
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
