Thread: Main() arguments

I am trying to learn more about main() taking arguments. I have tried creating a type of calculator program where you would use this syntax from the command line to calculate.

progname 1 + 1

I am having a problem with the operator part. I know that they will not show up as char type, so would I need to use their ASCII decimal form with my switch statement? Or how can I take different argument types such as, int, char, int?

Here is my lame code:

Code:

#include <iostream>
using namespace std;

int main(int *argv)
{
	switch(argv[2])
	{
	case '+': cout << argv[1]+argv[2]; break;
	case '-': cout << argv[1]-argv[2]; break;
	case '*': cout << argv[1]*argv[2]; break;
	case '/': cout << argv[1]/argv[2]; break;
	default: cout << "\nIncorrect usage.\n";
	}
	return 0;
}

Maybe something like this :

Code:

#include <iostream.h>
#include <fstream.h>
#include <stdlib.h>
#include <conio.h>


int main( int argc, char *argv[] )
{
	int number1 = atoi(argv[1]);
	int number2 = atoi(argv[3]);
	char type = *argv[2];

	switch(type)
	{
	case '+': cout << number1+number2; break;
	case '-': cout << number1-number2; break;
	case '*': cout << number1*number2; break;
	case '/': cout << number1/number2; break;
	default: cout << "\nIncorrect usage.\n";
	}

	return 0;
}

Probably should add some error checking aswell.

Some compiler support differen´t syntax for main. Check your compiler documentation - maybe you´ll find one which suits you better...

Thank you all.