Array names and char*'s

I was just wondering about character array offsets and
array names. If I declare:
char* a;
char* theString[]="Hello World";
a=theString;
a++;

Will a[0] now show 'e'?

A minor correction:

Code:

char* a; 
char theString[]="Hello World";  // Notice no '*' after char
a=theString;
a++;

The variable a is not an array so you really shouldn't be using the [] array indexing scheme. After the above code is run, a will point to the second element of theString which means that *a will equal 'e'.

Look at my program, in my case, it print's 'e':

Code:

#include <stdio.h>

int main(void)
{
    char *ptrStr;
    char *str = "Hello World";
    
    ptrStr = str;
    printf("%c\n",*(++ptrStr));
    getchar();
    return 0;
}

Thanks. This means array names are much more powerful than I thought!