IF within a FOR loop, continuing saga...

[Robert_Ingleby]

Dear CProgramming.com

I am trying to get a program to print the following Cayley table on screen:-

12345678
23456781
34567812
45678123
56781234
67812345
78123456
81234567

The problem is that my code prints this:-

12345678
23456789
345678910
4567891011
56789101112
678910111213
7891011121314
89101112131415

I can see why it is doing this. Its because the variable 'b' reaches 9 and at a this point it needs to be reset to 1.

My code is as follows:-


#include <stdio.h>

int main (void)

{
int a = 1;
int b = 1;
int c = 1;
int d = 1;

printf("Cayley Table\n\r");

while (a<=8)
{
b=d;
for (c=1; c<=8; b=b+1,c=c+1) ***** printf("%d",b);
printf("\n");
d=d+1;
a=a+1;
}

return 0;
}

At the point marked with 5 stars, the line "if(b>=8)b=1" needs to be added, the problem is the compiler comes up with "EXPRESSION SYNTAX" errors. I cannot use any semicolon near this bit of code or the program will not check to see if 'b' has reached 9 before resetting it back to 1 within the loop using variable 'c'.

I did post a suggestion here the day b4 yesterday and have tried what was suggested but
I could not get it to work. Please copy the code into a compiler and try it, you will see then what my problem is.

I have tried for AGES many different ways of trying to get this program to work
but without success. Whoever can help me complete this deserves a medal.

Thank-you once again.

Rob.

[Salem]

#include <stdio.h>
int main(void) {
    int a = 1;
    int b = 1;
    int c = 1;
    int d = 1;
    printf( "Cayley Table\n\r" );
    while(a<=8) {
        b=d;
        for(c=1; c<=8; b=b+1,c=c+1) {
            if(b >= 8) b = 1;
            printf( "%d",b );
        }
        printf( "\n" );
        d=d+1;
        a=a+1;
    }
    return 0;
}

Oh well........................

[Engineer]

Salem, you beat me to it.

I had a meeting at work.

here is the code i came up with:

#include <stdio.h>

int main (void)

{
int a = 1;
int b = 1;
int c = 1;
int d = 1;

printf("Cayley Table\n\r");

while (a <= 8)
{
b=d;
for (c = 1; c <= 8; b++, c++){
if(b == 9){
b=1;
printf("%d",b);
}
else
printf("%d",b);
}
printf("\n");
d=d+1;
a=a+1;
}

return 0;
}