Help with validation

**boontune** · 01-10-2003

Hi Guys,

Can you have a browse through my code and see if you can see a problem.

The problem i am having is, when i enter the second number and validate it as wrong ie, more than 6 digits it returns to begining asking for the fisrt num0ber again (This is right) but then it will not accept a valid number it just keeps jumping back to the beginning asking for the first number... can anyone help?

Here are the two functions that i am using: -

Code:

void calc()
{
clrscr();
cout << "Please enter your first number:";
cin >> num1;

validation1();

cout << "Please enter your second number:";
cin >> num2;

validation1();

cout << "Please select an operator + - * / %";
cin >> option1;

switch (option1)
{
case '+': add();
break;
case '-': subtract();
break;
case '*': multiply();
break;
case '/': divide();
break;
default: cout << "invalid";
}
}

void validation1()    // start of validation1 function
{

length1 = strlen(num1);
convertnum1 = atof(num1);
length2 = strlen(num2);
convertnum2 = atof(num2);

if (length1 <= 6 && convertnum1 > 0 && convertnum1 < 1000)
{
}


if (length2 <= 6 && convertnum2 > 0 && convertnum2 < 999)
{
}

else if (length1 > 6 || length2 > 6)
{
calc();    // if false returns to calculator funtion
}

}// end of validation function

**shiv_tech_quest** · 01-10-2003

Hi,

I haven't taken time to read your code completely, but I believe I understand your problem.

Let us say, you are accepting a value X from the keyboard into a character variable called ch;

cin >> ch;

You would have entered X and then pressed the enter-key. The symbol X is stored into ch, but the input stream still consists the enter-key. Its not yet flushed.

so you could try the c-function

fflush(stdin);

This would flush your input stream and things might work as wished.

**minesweeper** · 01-10-2003

Code:

else if (length1 > 6 || length2 > 6)
{
calc();    // if false returns to calculator funtion
}

This doesn't return back to calc(), this calls it. So all your program is doing running the first three lines of calc() over and over again. You might want to define validation1 as returning an int and then replacethis code with:

Code:

else if (length1 > 6 || length2 > 6)
{
return 0;    // if false returns to calculator funtion
}

Also

Code:

if (length2 <= 6 && convertnum2 > 0 && convertnum2 < 999)
{
}

What's thepurpose of this? You are evaluating a condition but then not doing anything if it is true.

Your code is a little confusing. I assume that num1 etc are characters as you have used string functions on them, but that leads me to ask why you named them num1 etc.

**minesweeper** · 01-10-2003

hmmmm, I'm also confused by the comment in

Code:

else if (length1 > 6 || length2 > 6)
{
calc();    // if false returns to calculator funtion
}

if what is false? For calc() to be called, the condition must be evaluated to true, not false.

**boontune** · 01-10-2003

Cheers guys,

As you can tell im quite new to this C++,

I know to myself what i mean, but to experianced programmers like yourselfs i guess it does look abit out of place!

I will give your sugestions a try and let you know how i got on..

Thanks to everyone who posted

Boontune

**boontune** · 01-10-2003

Please tell me if im wrong,

What the idea is with the validation function is to check that the input number is < or = to 6 digits long and in the range 0 - 1000,

if it passes the validation i want it to return to calc(),
and continue running the calc() function, this is why i left it blank in the IF statement, any ideas of what i should do there?

Because i thought that if it passed the IF statement it would return to calc and ask for the second number.....

Cheers guys

**alpha** · 01-10-2003

you can turn the validation function into an int or bool instead of void. if the number meets the conditions, return true or some int, else return false. ex.

Code:

bool validation() {
    if (length1 <= 6 && convertnum1 > 0 && convertnum1 < 1000)
        return true;
    else
        return false;
}

think about it...

**minesweeper** · 01-10-2003

boontune, alpha provided a good example validation function.

A little about 'if' statements:

An if statement doesn't impede the execution of the rest of the function if the condition evaluates to false, it simply means that the code written inside the open and closed parentheses immediately after the statement won't be executed. For example:

Code:

//code before 'if' statement
if (condition evaluating to false)
{
funtion();
}
//code after 'if' statement

Code:

//code before 'if' statement
if (condition evaluating to true)
{
funtion();
}
//code after 'if' statement

In both of these examples the code before and after the 'if' statement block will be executed, the only difference is that, in the second example 'function()' is called in between the two sections of code whereas in the first example it isn't. Is that any clearer?

**boontune** · 01-10-2003

Yeah i think so!

Thanks alot to everyone who chipped in!

Boontune

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