vector problem...

Theres a small problem here.Please read through the code.

Code:

---


#include <vector>


using namespace std ;
vector<char*> position ;
void pf(char* a)
{
 //char* m = a ;
 position.push_back(a);


}

int main(void)
{

pf("dog");
position.push_back("cat");
position.push_back("bear");
position.push_back("mouse");
position.push_back("horse");
sort(position.begin(),position.end()) ;
// why doesn't this sort work?? i want the cat, bear etc.. to be sorted alphabetically.


typedef vector<char*>::iterator VI ;

for( VI p = position.begin() ; p != position.end() ; ++p)
{
cout << *p << endl;
}

position.erase(position.begin() , position.end());
// I have already erased the vector called position here .

for( VI p = position.begin() ; p != position.end() ; ++p) 
                                          // now i want to
{                                      // print the elements again but it doesnt
                                        // print at all.i know that its all gone
                                        // but shouldn't it print garbage
                                      //values???
cout << *p << endl;
}

}

---

1. The sorting criterion wont work for char* as they are pointers....and the comparison operators (like '<') dont operate that way for pointers.......use std::string to get the desired result

Code:

---

#include <vector>
#include <string>
#include <iostream>

using namespace std ;



int main(void)
{

        vector<std::string> position ;

        position.push_back("dog");
        position.push_back("cat");
        position.push_back("bear");
        position.push_back("mouse");
        position.push_back("horse");
        sort(position.begin(),position.end()) ;


        typedef vector<string>::iterator VI ;

        for( VI p = position.begin() ; p != position.end() ; ++p)
        {
                cout << *p << endl;
        }

}

---

2. The vector will not hold junk values.....erase gets rid of the elements and decreases the size of the container......so therefore no elements will be obtained from the iterators