
how can i express
Hello Everone.
I hope somebody can 'pointer' me in the correct direction ...my problem is in char/ascii conversions
i want to outpuit a Letter grade for an average that i have caluculated in the previous fx but i am unsure if i need to call
an "A" 65?. I will be returning this "grade" to a previous function that calls all of my calculations, and THEN drops them into their place in my struct. Hope that's enuf info...
I am getting 2 types of errors on the following Fx syntax
1.
'<=' : unsafe use of type 'bool' in operation
2.
'A' : undeclared identifier
Can someone perhaps tell me what is off about my expression?
This is one teeny piece of a huge puzzle i am working on and i 'm finding myself kinda stuck and help is much appreciated...and hopefully when i have a little more mouseexperience i will be able to return the favor someday....
Thx!
Mouse
Code:
char CalcGrade(double AV){
{
if (90<= AV <= 100)
return A;
else if (80<= AV <= 90)
return B;
else if (70<= AV <= 80)
return C;
else if (60<= AV <= 70)
return D;
else return F;
}
}

Do this:
return 'A';
instead of
return A;

Also your if expressions are incorrect, hence the unsafe bool warning.
Try this, notice I've change some '<=' into '<'.
Code:
if (90 <= AV <= 100)
return 'A';
else if (80 <= AV < 90)
return 'B';
else if (70 <= AV < 80)
return 'C';
else if (60 <= AV < 70)
return 'D';
else return 'F';
You should note that if it is possible for someone to be given 101%, your function is going to assign them an 'F'.

Re: how can i express
Code:
char CalcGrade(double AV)
{
if(AV >= 90) return 'A';
if(AV >= 80) return 'B';
if(AV >= 70) return 'C';
if(AV >= 60) return 'D';
return 'F';
}

thanks alot guys!!
thanks so much...it's the little things that make the BIG Picture clearer!!
MUCH appreciated!
Mouse

Quote:
Originally posted by Davros Also your if expressions are incorrect, hence the unsafe bool warning.
Try this, notice I've change some '<=' into '<'.
Code:
if (90 <= AV <= 100)
return 'A';
else if (80 <= AV < 90)
return 'B';
else if (70 <= AV < 80)
return 'C';
else if (60 <= AV < 70)
return 'D';
else return 'F';
You should note that if it is possible for someone to be given 101%, your function is going to assign them an 'F'.
Nonononononono!!! You can't string logical comparisons together like that!
For example
90 <= AV <= 100
Won't check if AV is between 90 and 100
A logical operator like <= returns a boolean value (true or false).
So in actuality, what
90 <= AV <= 100
does is
90 <= AV
that will return either 1 or 0
then, it will compare that 1 or 0 with 100
So if AV was greater than or equal to 90 it would return 1, and then it would do
1 <= 100 which would return true.
Since the first expression would return either 1 or 0 the expression would always be true.
What you really want to do is make 2 separate comparisons and connect them with &&
like
if( 90 <= AV && AV <= 100 )