Trouble with a class variable

I have a class called test with a public variable called abc in it,
this variable can be altert in the main (using "test test;" as a
constructor) but when i try to alter it in a funtion of another class
it goes wrong! (again using the "test test;" constructor)

You should know that when im altering it i actually calling a
function who alters it like:

test::altervar(string newvar)
{
abc=newvar;
}

Now when i call another function it still recognizes the previous
value of abc (given in main in this case) to be its value

Weird! can't figure it out myself, thx for any help you can give me

Post your code, itt'l make your question loads easier to answer than trying to interpret your vague description.

Aya, thank you very much:p

Code:

---


 class test
{
public:

void alterabcvar();
void printabc();

string abc="test1";

}

void test::alterabcvar(string newabc)
{
abc=newabc;  <--- everything fine here abc became newabc
}

void test::printabc()
{
cout << abc; <--- here it only prints test2 once????
}

void main() // <--- HAHA FEAR ME I USE VOID!!!! HAHAHA
{
test test;
test2 test2;

test.alterabc("test2");
test.printabc();

test2.test;
test.printabc();

}

class test2
{
public:
void test();
}

void test2::test()
{
test test;
test.alterabc("test3");
}

---

> string abc="test1";
You can't do that, you need to initilize class members from a constructor. If you need help with those I suggest you check the tutorials at this website.

> test test;
Can't do that, you need to use a unique name for your class instances (can't be the same name as the class)

> void test2::test()
{
test testvar;
test.alterabc("test3");

}

I don't know what you're trying to achieve here, but again, you can't use test for a variable name. If you're trying to change the value of the test variable in main you'll need to pass it to the function. You also made numerous typos like "test:rintabc()"
Fix those too.

I dont know if this is generating an error for you but you must include a semicolon after the class.

should look like this

Code:

---

class test
{
public:

void alterabcvar();
void printabc();

string abc="test1";

}; //add semicolon

---

also add it for test 2 class

Quote:

---

Originally posted by Salem
> void main() // <--- HAHA FEAR ME I USE VOID!!!! HAHAHA
How nice - taking pride in your ignorance

Probably not worth trying to teach you anything (there's no guarantee that you'll pay any attention to it) if you continue to do this - after all, if you're willing to break 1 rule, why not break them all?

---

Not ment as an attack to you, its just that so many people tell
me to use int and i still dont see the point of it, maybe you can
convince me?

Anyway,all those little mistakes you found in my code is a result
of typing an example from my head, it wasnt copy pasted,
but the variables in my other class start to act weird now too,
maybe im using them wrong.
Is there a tutorial about using variables of classes?

Code:

---

void alterabcvar();

---

Code:

---

void test::alterabcvar(string newabc)
{
abc=newabc;  <--- everything fine here abc became newabc
}

---

Missmatch! Also why not pass newabc as a reference?

P.S Don´t use void main() !!!!

Quote:

---

Originally posted by ripper079

Code:

---

void alterabcvar();

---

Code:

---

void test::alterabcvar(string newabc)
{
abc=newabc;  <--- everything fine here abc became newabc
}

---

Missmatch! Also why not pass newabc as a reference?

P.S Don´t use void main() !!!!

---

He, As i just said i typed that code from my head, and thus
mistakes are bound to happen, i dint have that mistake in the
code

But for that main,so the program should return a valua
usually a status, if it whent wrong or right, but what if
you have a exit(1); in a function of yuor program does it
return a value then too?

(not that i use such a devil spaghetti code command)

Yes. Actually, the argument for exit() is the value that is returned. So, if you use exit(1), then the integer value of 1 is returned to the environment/OS.