i don't understand this whatsoever

I am still not getting this whole loop thing. :( I have to make a pyarmid using *'s with a nested loop program and I don't get it. I think I'll put my fist through this computer.

Help?

Uhh well ur title isn't very convincing in the first place and its homework but i'll help you anyways...

try this:

Code:

---

#include <iostream.h>
int main()
{
int nrows = 5; //number of rows
 for(int x=0; x<nrows; x++)
 {
  if(x == 0)
  {
  cout<<"*";
  }
  if(x == 1)
  {
  cout<<"\n**";
  }
  if(x == 2)
  {
  cout<<"\n***";
  }
  if(x == 3)
  {
  cout<<"\n****";
  }
  if(x == 4)
  {
  cout<<"\n*****";
  }
  if(x == 5)
  {
    cout<<"\n******";
  }
 }
return 0;
}

---

this is one half of the pyrimide and you can do the other one

why use all those if's?

use a nested loop

Code:

---

#include<iostream>

using namespace std;


int main(){

        int i;
        for(i=0;i<6;i++){
                for(int j=i;j>0;j--)
                        cout<<"*";
                cout << endl;
        }
        for( ;i>0;i--){
                for(int j=i;j>0;j--)
                        cout<<"*";
                cout << endl;
        }
}

---

or if you want it small and compact

Code:

---

#include<iostream>
int main(){
        char *x="*******";
        int i=0;
        for(;i++<7;)printf("%.*s\n",i,x);
        for(;i-->0;)printf("%.*s\n",i,x);
}

---

Quote:

---

Originally posted by beege31337
or if you want it small and compact

---

I can beat that ;)

Code:

---

#include "MyPyramid.h"
int main(){ PrintMyPyramid(); return 0; }

---

Heres a neat solution

you need this include<iomanip.h>


for (int i =0;i<15;i++)//loop to print pyrimid of asterisks
{
if(i==0)cout<<setw(6);
if (i ==1)cout<<setw(5)<< endl;//*
if (i ==3)cout<<setw(4)<<endl; //**
if (i ==6)cout<<setw(3)<<endl;//***
if (i ==10)cout<<setw(2)<<endl;//****
cout<<"* "; //*****
}