This is a discussion on operator->(), making one object look like another within the C++ Programming forums, part of the General Programming Boards category; Why can't I do this? It's used in this example: http://www.parashift.com/c++-faq-lit...html#faq-16.21 Or am I missing the point in overloading operator->? ...
Why can't I do this? It's used in this example: http://www.parashift.com/c++-faq-lit...html#faq-16.21 Or am I missing the point in overloading operator->?
Code:struct a { a() : one(1), two(2) {}; int one; int two; }; class b { public: b() {}; a operator->() { return m_a; } private: a m_a; }; int main() { b myb; cout << myb->one; return 0; }
Rolling out the smart pointers - eh?
>>a * operator->() { return &m_a; }
Code:int main(void){srand(time(0));for(double l=rand(),l0=0,l00=0;;l0+=0.1){for(double l000=0;l000 <1;l000+=.001,l+=((double)rand()/RAND_MAX)/0x64,l00+=((sin(l*0x8*atan(l0)*l000-(l0*0x8*atan (l)))*0.5)+0.5)){l00-=floor(l00);for(size_t l0000=0,l00000=(size_t)(0x50*(l00));l0000<l00000;++l0000 )putchar(0x20);putchar(0x61+(int)((double)rand()/RAND_MAX*0x1a));putchar('\n');}}return 0;}
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