Finding Average of floats
can some one tell me whats wrong with this program. i'm trying to find average of 10 floats and how do i use code tags?
Code:#include <iostream.h> #include <iomanip.h> void main() { // declare all variables float a[10]; // ask user for numbers cout << "What are the floating point numbers?" << endl; cin >> a[10]; float average; average = ((a[1]+a[2]+a[3]+a[4]+a[5]+a[6]+a[7]+a[8]+a[9]+a[10])/10); cout << "The average is " << average << endl; }
I added the code tags for you, but here's how you use them:
put [code] before your code, then [/code] after your code and voila...check the link in my signture for more...
(looks like this when typing)
[code]
cout << "hi";
[/code]
well, first you need to actually get the floats from the user
code tags areCode:for(int i = 0; i < 10; ++i) { cout<<"Enter number: "; cin>>a[i]; }
[ code ]
and
[ /code ]
without the spaces.
thank you very much for adding code tags. i haven't used the board since a while and forgot. And thanks for that program help.
Thank you.
Remember the base of an array is 0Code:#include <iostream.h> int main() { float a[10]; cout << "What are the floating point numbers?" << endl; for(int i = 0; i < 10; i ++) { cin >> a[i]; } float average; average = ((a[0]+a[1]+a[2]+a[3]+a[4]+a[5]+a[6]+a[7]+a[8]+a[9])/10); cout << "The average is " << average << endl; return 0; }
I am against the teaching of evolution in schools. I am also against widespread
literacy and the refrigeration of food.
Now how would i make the program to display which numbers have exceeded the average?
You can use a conditional statement (like an if...)
Mr. C: Author and Instructor
that would be pretty simple..
for each score
if score > average
print score is higher than average
I can't resist...
Code:cout << "Numbers that exceed average: "; for(int j = 0; j < 10; j ++) { if(a[j] > average) { cout << a[j] << " "; } }
I am against the teaching of evolution in schools. I am also against widespread
literacy and the refrigeration of food.
