input/output

This is a discussion on input/output within the C++ Programming forums, part of the General Programming Boards category; Hello everyone, I'm trying to figure out how input/output files work. I got warnings, and it compiled, but when I ...

  1. #1
    JCK
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    input/output

    Hello everyone,

    I'm trying to figure out how input/output files work. I got warnings, and it compiled, but when I tried to run the program, it gave me

    input file failed
    press any key to continue

    I thought we are supposed to list the directory, and my input file is saved in the same folder, and the same directory, any suggestions??

    Thanks a million!!

    p.s. this is only the partial code.

    Code:
    int main()
    {
      string first_name;            //declare string variable first name
      string last_name;             //declare string variable last name
      string gender;                //declare string variable gender
      int age;                      //declare int variable age
      string type_coverage;         //declare string variable type of coverage
      string club_member;           //declare string variable health club
                                    //member
      string smoker;                //declare string variable smoker
      int zip_code;                 //declare int variable zip code
      float basic_premium;          //declare int variable basic premium
      float discount_premium;		//declare int variable discount premium
      float premium;				//declare int variable premium
    
    
      ifstream inFile;              //declare file streams
      ofstream outFile;
    
      inFile.open("C:\Windows\C++\proj4.in.txt");      //opens the input file
      outFile.open("C:\Windows\C++\proj4.out.txt");    //opens the output file
    
      if(!inFile)
      {
        cout << "Input file failed!" << endl;
        return 1;                   //terminates the program if input fails
      }

  2. #2
    PC Fixer-Upper Waldo2k2's Avatar
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    Code:
    if (!inFile.is_open())
    {
        //terminate program
    }
    notice the .is_open() part
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  3. #3
    JCK
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    Hi, Waldo2k2,

    Thanks for the suggestions.... however, I tried it and it gave me the same thing.... I think the program can't find the input file.....
    I tried my last project in UNIX system without the "C:\\windows\C++" part and it works with the same structure.

    Now, I'm trying to modify the same program but using the visual C++ so it is easier to debug, and I saved the input file in the same folder in the directory, but it would not work....... any more suggestions??

    Thanks so much!!

  4. #4
    PC Fixer-Upper Waldo2k2's Avatar
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    oh wow, i missed the biggest mistake,
    Code:
    inFile.open("C:\Windows\C++\proj4.in.txt");      //opens the input file
    since you used unix before you used forward slashes for the path, in windows it's the backslashes, the problem is in c++ the backslash is used for character escape sequences. So, you need to change \ to \\. then it will work. I bet those are the warnings you're getting as well.

    And by the way leave is_open() as it is, that is the correct way to do it. You can also save time by doing:
    Code:
    ifstream inFile("c:\\windows\\c++\\proj4.in.txt");
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  5. #5
    JCK
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    Hi Waldo2k2

    Cool!!! It worked!!! and it made sense too... it is funny that you learned the mistakes that you made and you realized that
    "duh! Didn't I know this before?!!" I guess that comes with experiences.....

    Thanks so much again!!

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