I know that I can use string instead of char when declaring a char or an array
So here is a function prototype written in c
void decrypt(const char in[],char out[]);
can I re-write it in c++ like this:
void decrypt(const string in[], string out[]);
This is a discussion on string within the C++ Programming forums, part of the General Programming Boards category; I know that I can use string instead of char when declaring a char or an array So here is ...
I know that I can use string instead of char when declaring a char or an array
So here is a function prototype written in c
void decrypt(const char in[],char out[]);
can I re-write it in c++ like this:
void decrypt(const string in[], string out[]);
No. It would be:
void decrypt(const string in, string out);
...since a single string is an array of chars...
Code:int main(void){srand(time(0));for(double l=rand(),l0=0,l00=0;;l0+=0.1){for(double l000=0;l000 <1;l000+=.001,l+=((double)rand()/RAND_MAX)/0x64,l00+=((sin(l*0x8*atan(l0)*l000-(l0*0x8*atan (l)))*0.5)+0.5)){l00-=floor(l00);for(size_t l0000=0,l00000=(size_t)(0x50*(l00));l0000<l00000;++l0000 )putchar(0x20);putchar(0x61+(int)((double)rand()/RAND_MAX*0x1a));putchar('\n');}}return 0;}
Well you would want to pass out by reference.
Code:void decrypt(const string in, string &out);
heh, that's what I meant![]()
Code:int main(void){srand(time(0));for(double l=rand(),l0=0,l00=0;;l0+=0.1){for(double l000=0;l000 <1;l000+=.001,l+=((double)rand()/RAND_MAX)/0x64,l00+=((sin(l*0x8*atan(l0)*l000-(l0*0x8*atan (l)))*0.5)+0.5)){l00-=floor(l00);for(size_t l0000=0,l00000=(size_t)(0x50*(l00));l0000<l00000;++l0000 )putchar(0x20);putchar(0x61+(int)((double)rand()/RAND_MAX*0x1a));putchar('\n');}}return 0;}